Answer:
The change in temperature per minute for the sample, dT/dt is 71.
°C/min
Step-by-step explanation:
The given parameters of the question are;
The specific heat capacity for glass, dQ/dT = 0.18 (kcal/°C)
The heat transfer rate for 1 kg of glass at 20.0 °C, dQ/dt = 12.9 kcal/min
Given that both dQ/dT and dQ/dt are known, we have;


Therefore, we get;


For the sample, we have the change in temperature per minute, dT/dt, presented as follows;

Answer:
y = 2 ( x − 1 ) ^ 2 + 2
Step-by-step explanation:
y = a ( x − h ) ^ 2 + k
where vertex is (h,k) = (1,2)
h=1, k=2
y = a ( x − 1 ) ^ 2 + 2
sub ( 3,10)
10 = a (3 - 1)^2 + 2
a=2
y = 2 ( x − 1 ) ^ 2 + 2
ANSWER: 2484
(Alternative forms): 2.484 × 10³
Answer:
Step-by-step explanation:
12 is F