All categories

3 years ago

The difference between 8 and a number is 5.

Mathematics

2 answers:

pav-90 [236]3 years ago

3 0

Answer:

the answer is 3.

Step-by-step explanation:

Difference between means to subtract.

8 - 5 = 3

vekshin13 years ago

3 0

Answer:

8- a = 5

Step-by-step explanation:

You might be interested in

Use the graph below to determine the number of solutions the system has.

mixas84 [53]

Answer:

one

Step-by-step explanation:

I think, there were 4 lines and the two lines are reaching each other

8 0

3 years ago

Can anyone help me ASAP!

slega [8]

Answer:

Step-by-step explanation:

6 0

3 years ago

How do you find what the IQR

jek_recluse [69]

Bow hello IQR is 21 + 1 -1 = 21

8 0

3 years ago

Read 2 more answers

Which corresponds to the perimeter of triangle ABC?

____ [38]

Answer:

The answer to your question is: letter C

Step-by-step explanation:

Data

A (-5 , -1)

B (-2, 3)

C (6, -3)

Perimeter = ?

Formula

$d = \sqrt{(x2 - x1)^{2} + (y2 - y1)^{2} }$

distance AB $d = \sqrt{(-2 + 5)^{2} + (3 + 1)^{2} }$

$d = \sqrt{(3)^{2} + (4)^{2} }$

$d = \sqrt{(9 + (16) }$

$d = \sqrt{25}$

d = 5

Distance BC $d = \sqrt{(-3 - 3)^{2} + (6 + 2)^{2} }$

$d = \sqrt{(-6)^{2} + (8)^{2} }$

$d = \sqrt{36 + 64}$

$d = \sqrt{100}$

d = 10

Distance AC $d = \sqrt{(-3 + 1)^{2} + (6 + 5)^{2} }$

$d = \sqrt{(-2)^{2} + (11)^{2} }$

$d = \sqrt{4 + 121}$

$d = \sqrt{125}$

d = 11.2

Perimeter = 5 + 10 + 11.2

= 15 + $\sqrt{125}$

4 0

4 years ago

Read the ques

Dafna11 [192]

Answer:

0.25feet

Step-by-step explanation:

The equation is not well written. Let the equation of the height be modelled as;

h = -16d²+8d+4

The velocity of the ball is zero at its maximum height.

Velocity = change in displacement/time

v = dh/dd

Differentiate

v = -32d+8

Since dh/dd = v = 0

0 = -32d+8

Add 32d to both sides

0+32d = 8

32d = 8

Divide both sides by 32

32d/32 = 8/32

d = 1/4

d = 0.25feet

Hence the maximum height of the tennis ball is 0.25feet

Note that the modeled equation was assumed. You can apply the same calculation to any equation given

3 0

3 years ago