Answer:
The 1st graph will be perfectly matching the conditions.
Step-by-step explanation:
A wholesaler requires a minimum of 4 items in each order from its retail customers.
The manager of one retail store is considering ordering a certain number of sofas, x and a certain number of pillows that come in pairs, y.
Therefore, for y = 0, x ≥ 4 and for x = 0, y ≥ 2 to make the order of 4 items or more.
Therefore, the equation for the order to be of 4 items will be
x + 2y = 4.
So, the 1st graph will be perfectly matching the conditions. (Answer)
Answer:
It is a function Jonny!
Step-by-step explanation:
Hello! I would say to Jonny:
Jonny! A function is a relation between two sets, in which every element of the first set (domain) is assigned only one element of the second set (codomain).
If you have serveral elements of the first set with the same corresponding element of the second set it is correct to call that relation a function.
However, if you have an element of the first set for which your relation can relate to more than one element of the second set, then Jonny, that is not a function.
In the present case, every student ID number can only be realted to a number of the set {9, 10, 11, 12}, a student cannot have more than one current grade level. Therefore, that relation is in fact a function
Answer:
1
Step-by-step explanation:
(f/g)(x)
= 
=
← substitute x = 2 into the expression
= 
= 
= 
= 1
Answer:
the answer is E, right?
Step-by-step explanation: