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2 years ago

Give 4 reasons to get a pug, and 4 to get a papillion

Mathematics

2 answers:

Georgia [21]2 years ago

8 0

Answer:

Pugs are natural cuddlers.

Pugs tend to be smart, observant, and quick learners. ...

Pugs are relatively low-maintenance.

With pugs, a little exercise goes a long way.

Pugs get along well with other animals

Step-by-step explanation:

please mark me as brainlist

chubhunter [2.5K]2 years ago

5 0

Answer:

Her answer is right .... ....

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If the family pays $25 what is the exact amount of change they should receive

Bingel [31]

What’s the full question? you only put part of it on here

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2 years ago

Which shows 4x+2y=-16

mrs_skeptik [129]

4x+2y=-16
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3 years ago

What is the result of 96 divided by 6? Use the model to find the answer.

gregori [183]

Answer:

the answer is 16

Step-by-step explanation:

i dont see any model but thats the result. (also so u don't waste points u can just use a calculator for things like this in the future)

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2 years ago

Read 2 more answers

X Find the value of x. Show 3 10 your work.

pickupchik [31]

Step-by-step explanation:

Hello, there!!!

Let ABC be a Right angled triangle, 

where, AB = 3

BC= 10

and AC= x

now,

As the triangle is a Right angled triangle, taking angle C asrefrence angle. we get,

 h= AC = x

p= AB = 3

b= BC= 10

now, by Pythagoras relation we get, 

 $h = \sqrt{ {p}^{2} + {b}^{2} }$ 

 $or ,\: h = \sqrt{ {3}^{2} + {10}^{2} }$ 

by simplifying it we get, 

h = 10.44030

Therefore, the answer is x= 10.

Hope it helps...

7 0

3 years ago

how much antifreeze 25% antifreeze and 50% antifreeze should be combined to give 40 gallon of 30% antifreeze?

VARVARA [1.3K]

32 gallons of 25 % antifreeze should be combined with 8 gallons of 50 % antifreeze to get 40 gallon of 30% antifreeze

<h3>Solution:</h3>

From given,

Final mixture is 40 gallon

Let "x" be the gallon of 25 % antifreeze

Then, (40 - x) is the gallon of 50 % antifreeze

Therefore, according to question,

"x" gallons of 25 % antifreeze should be combined with (40 - x) gallons of 50 % antifreeze to get 40 gallon of 30% antifreeze

<h3>Therefore, we frame a equation as:</h3>

25 % of x + 50 % of (40 - x) = 30 % of 40

Solve for "x"

$\frac{25}{100} \times x + \frac{50}{100} \times (40-x) = \frac{30}{100} \times 40\\\\0.25x + 0.5(40-x) = 12\\\\0.25x + 20 - 0.5x = 12\\\\0.25x - 0.5x = 12 - 20\\\\-0.25x = -8\\\\0.25x = 8\\\\Divide\ both\ sides\ by\ 0.25\\\\x = 32$

Thus, 32 gallons of 25 % antifreeze is used

Then, (40 - x) = (40 - 32) = 8

Thus 8 gallons of 50 % antifreeze is used

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3 years ago