The geometric sequence is found in the relationship between consecutive terms that is constant.
In this problem, as I understand it, none of the functions forms a geometric sequence.
The functions that form a geometric sequence have the form
f (x) = h (a) ^ n where "a" is the constant relation between the successive terms.
If you wrote the function "f (x) = - 2 (3/4) x", you wanted to write instead:
f (x) = - 2 (3/4) ^ x
So that would be the function that forms a geometric sequence, where the relation between the consecutive terms is 3/4.
You can test it by dividing f (x) / f (x-1)
Then you will see that the result of that division will be 3/4.
Answer:
your answer would to your question is d
The option that best describes the experiment is accurate and reproducible.
<h3>What option describes the data?</h3>
All the values from the experiment are close in value to the accepted value. This indicates that the experiment is accurate. Two experiments yield the same values. This indicates that the experiment is reproducible.
Here is the table used in answering the question:
Accepted Value: 130
Experiment 1 129
Experiment 2 131
Experiment 3 129
Experiment 4 132
To learn more about experiments, please check: brainly.com/question/14019529
#SPJ1
I’m not sure, but i think that you have to take the volume equation, and plug in the other variables (volume, area) to find the height
<h3>
Answer: False</h3>
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Explanation:
I'm assuming you meant to type out
(y-2)^2 = y^2-6y+4
This equation is not true for all real numbers because the left hand side expands out like so
(y-2)^2
(y-2)(y-2)
x(y-2) .... let x = y-2
xy-2x
y(x)-2(x)
y(y-2)-2(y-2) ... replace x with y-2
y^2-2y-2y+4
y^2-4y+4
So if the claim was (y-2)^2 = y^2-4y+4, then the claim would be true. However, the right hand side we're given doesn't match up with y^2-4y+4
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Another approach is to pick some y value such as y = 2 to find that
(y-2)^2 = y^2-6y+4
(2-2)^2 = 2^2 - 6(2) + 4 .... plug in y = 2
0^2 = 2^2 - 6(2) + 4
0 = 4 - 6(2) + 4
0 = 4 - 12 + 4
0 = -4
We get a false statement. This is one counterexample showing the given equation is not true for all values of y.
