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kipiarov [429]
2 years ago
14

Identify the equation modeled below,and then find its solution

Mathematics
1 answer:
Usimov [2.4K]2 years ago
8 0

Answer:

H

Step-by-step explanation:

4x-4=-x-1 = 3/5 or .6

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(cotx+cscx)/(sinx+tanx)
Butoxors [25]

Answer:   \bold{\dfrac{cot(x)}{sin(x)}}

<u>Step-by-step explanation:</u>

Convert everything to "sin" and "cos" and then cancel out the common factors.

\dfrac{cot(x)+csc(x)}{sin(x)+tan(x)}\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)}{1}+\dfrac{sin(x)}{cos(x)}\bigg)\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg[\dfrac{sin(x)}{1}\bigg(\dfrac{cos(x)}{cos(x)}\bigg)+\dfrac{sin(x)}{cos(x)}\bigg]\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)}{cos(x)}+\dfrac{sin(x)}{cos(x)}\bigg)

\text{Simplify:}\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)+sin(x)}{cos(x)}\bigg)\\\\\\\text{Multiply by the reciprocal (fraction rules)}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)cos(x)+sin(x)}\bigg)\\\\\\\text{Factor out the common term on the right side denominator}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)(cos(x)+1)}\bigg)

\text{Cross out the common factor of (cos(x) + 1) from the top and bottom}:\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)}\bigg)\\\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times cot(x)}\qquad \rightarrow \qquad \dfrac{cot(x)}{sin(x)}

6 0
3 years ago
There are 20 cities in the County of Newton. Their populations are shown in the bar chart below. The average population of all t
blagie [28]

Answer:

The answer is C/85,000

Step-by-step explanation:

6 0
2 years ago
X-5y=33<br> 5x-6y=70<br> solve the system by the addition method
BARSIC [14]

For this case we have the following system of equations:

x-5y = 33\\5x-6y = 70

We multiply the first equation by -5:

-5x + 25y = -165

Thus, we have the equivalent system:

-5x + 25y = -165\\5x-6y = 70

We add the equations:

-5x + 5x + 25y-6y = -165 + 70\\19y = -95\\y = - \frac {95} {19}\\y = -5

We find the value of the variable "x":

x-5 (-5) = 33\\x + 25 = 33\\x = 33-25\\x = 8

Thus, the solution of the system is:

(x, y) :( 8, -5)

Answer:

(x, y) :( 8, -5)

7 0
3 years ago
Question 3 0.6 pts The following two right triangles are similar.If side CB = 33. side AB = 12, and side DE - 4. what is the len
Leno4ka [110]

Answer:

EF = 11

Step-by-step explanation:

AD/DE = 3

Therefore, DC/3 = EF

33/3 = 11

8 0
3 years ago
Jake ate 1/6 of the chocolates the Jill came ate 1/5 of the remaining then mike ate 1/4 of the remaining then Sara ate 1/3 of th
ahrayia [7]

Answer:

  4 chocolates

Step-by-step explanation:

Before Luke started eating, there were 8. This is 2/3 of what Sara had to start with, so she started with 12. That is 3/4 of what Mike started with, so he started with 16.

Jill left 4/5 of what she started with, so she must have started with 20. Jake ate 1/6 and left 5/6, so 20 is 5 times the number Jake ate.

Jake ate 4 chocolates.

___

Jill ate 4; Mike ate 4; Sara ate 4; and Luke ate 4.

3 0
3 years ago
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