Graph the equation using intercepts. GIVING BRAINIEST TO WHOEVER HELPS ME AND GETS IT RIGHT

Mathematics

1 answer:

goldenfox [79]3 years ago

7 0

Answer:

the line with go from the y-intercept -10 to the x-intercept 8

step-by-step explanation:
5x - 4y = 40
x = 0
5(0) - 4y = 40
-4y = 40
/-4 /-4
y = -10
y = 0
5x - 4(0) = 40
5x = 40
/5 /5
x = 8
the line with go from the y-intercept -10 to the x-intercept 8

You might be interested in

Help please please help ASAP * please don’t answer if you don’t know

Julli [10]

Answer:

Your answer is x = 24 , y =8√3

Step-by-step explanation:

Sorry for late answer actually I was preparing for my exams. ❤

3 0

3 years ago

An item was bought for £3 000. It was sold for £1 800. What was the percentage loss? Please help

Gekata [30.6K]

Step-by-step explanation:

real real on the 11th July world population Day is celebrated on the table that day was across the world it is

6 0

3 years ago

Read 2 more answers

Select the choice that translates the following verbal phrase correctly to algebra:

Anestetic [448]

" the product " means multiply

km <== ur expression...which means k * m

4 0

3 years ago

Read 2 more answers

Write the time 8:30 then write this time in two other ways using words

guajiro [1.7K]

Half past eight or thirty minutes to nine

8 0

3 years ago

A ball is thrown from an initial height of 1 meter with an initial upward velocity of 15m/s. The ball's height h (in meters) aft

lakkis [162]

$\bf \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{h}=1+15t-5t^2}\implies \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{6}=1+15t-5t^2}\implies 0=-5+15t-5t^2 \\\\\\ ~~~~~~~~~~~~\textit{using the quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{5}t^2\stackrel{\stackrel{b}{\downarrow }}{-15}t\stackrel{\stackrel{c}{\downarrow }}{+5}=0 \qquad \qquad t= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}$

$\bf t=\cfrac{-(-15)\pm\sqrt{(-15)^2-4(5)(5)}}{2(5)}\implies t=\cfrac{15\pm\sqrt{225-100}}{10} \\\\\\ t=\cfrac{15\pm\sqrt{125}}{10}\implies t=\cfrac{15\pm\sqrt{5^2 \cdot 5}}{10}\implies t=\cfrac{\stackrel{3}{~~\begin{matrix} 15 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\pm ~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\sqrt{5}}{\underset{2}{~~\begin{matrix} 10 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}$

$\bf t=\cfrac{3\pm \sqrt{5}}{2}\implies t= \begin{cases} \frac{3+ \sqrt{5}}{2} \approx 2.618\\\\ \frac{3- \sqrt{5}}{2}\approx 0.382 \end{cases}$

8 0

3 years ago