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3 years ago

An image is 2 units to the left of the pre-image.

Mathematics

2 answers:

kap26 [50]3 years ago

7 0

Answer:

Santana’s reasoning is not correct. The translation should be 2 units to the left, not to the right.

Step-by-step explanation:

I got it right.

stepladder [879]3 years ago

5 0

Answer:

Santana's thinking is not correct, because the correct translation is 2 units to the left, not right.

Step-by-step explanation:

I just got that question and I got it right.

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6 165.1 159.2 163.5 174.8 173.2 177.6 174.3 164.1 171.4 find the median

Katen [24]

159.2, 163.5, 164.1, 171.4, 173.2, 174.3, 174.8, 177.6, 6165.1

mean= 835.9
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mode= N/A

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3 years ago

Find the sum of the first 8 terms in the following geometric series.

padilas [110]

Answer: 43690

Step-by-step explanation:

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3 years ago

The length of a rectangle board is 10 centimeters longer than its width. The width of the board is 26 centimeters. The board is

Troyanec [42]

Answer:

Area of each piece = 104 $cm^{2}$

Possible dimensions are 26 cm by 4 cm, 13 cm by 8 cm.

Step-by-step explanation:

Given that:

Dimensions of the rectangular board as:

Length of the board is 10 cm longer than its width.

Width of the board = 26 cm

Length of the board = 26 + 10 = 36 cm

The rectangular board is divided into 9 equal pieces.

To find:

Area of each piece and

the possible dimensions of each piece = ?

Solution:

First of all, let us calculate the area of bigger rectangular board.

Area of a rectangle is given by the following formula:

$Area = Length \times Width$

Area = 26 $\times$ 36 $cm^2$

Area of each smaller rectangle = $\frac{26\times 36}{9} = 104\ cm^2$

To find the possible dimensions, we need to find the factors of 104.

104 = 26 $\times$ 4

104 = 13 $\times$ 8

Therefore, the Possible dimensions are 26 cm by 4 cm

and

13 cm by 8 cm.

5 0

2 years ago

Would appreciate the help !

aleksandr82 [10.1K]

This is one pathway to prove the identity.

Part 1

$\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{1}{\tan(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\cot(\theta) = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)*\sin(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)(1-\cos(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 2

$\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 3

$\frac{\sin^2(\theta)+\cos^2(\theta)-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1}{\sin(\theta)} = \frac{1}{\sin(\theta)} \ \ {\checkmark}\\\\$

As the steps above show, the goal is to get both sides be the same identical expression. You should only work with one side to transform it into the other. In this case, the left side transforms while the right side stays fixed the entire time. The general rule is that you should convert the more complicated expression into a simpler form.

We use other previously established or proven trig identities to work through the steps. For example, I used the pythagorean identity $\sin^2(\theta)+\cos^2(\theta) = 1$ in the second to last step. I broke the steps into three parts to hopefully make it more manageable.

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2 years ago

Things that light up??

babunello [35]

Answer:

Candles, fireworks, sun, lights, Christmas tree, etc

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers