The expression factorized completely is (h +2k)[(h+2k) + (2k-h)]
From the question,
We are to factorize the expression (h+2k)²+4k²-h² completely
The expression can be factorized as shown below
(h+2k)²+4k²-h² becomes
(h+2k)² + 2²k²-h²
(h+2k)² + (2k)²-h²
Using difference of two squares
The expression (2k)²-h² = (2k+h)(2k-h)
Then,
(h+2k)² + (2k)²-h² becomes
(h+2k)² + (2k +h)(2k-h)
This can be written as
(h+2k)² + (h +2k)(2k-h)
Now,
Factorizing, we get
(h +2k)[(h+2k) + (2k-h)]
Hence, the expression factorized completely is (h +2k)[(h+2k) + (2k-h)]
Learn more here:brainly.com/question/12486387
For these kinds of questions you should first solve for x:
y +36 = x^2 ⇒ √y+36 = x
now the inverse of this equation is:
√x + 36 = y :)))
i hope this is helpful
have a nice day
-0.25 don’t know but I try
Answer:
B.) Associative Property of Addition
Step-by-step explanation:
This is because none of the numbers change places the only things that move are the parenthesis which correspond with the associative property.
Answer:
Step-by-step explanation:
K is located at -25
L is located at -15
just move 5 units away from J on both sides
hope this helps <3
