The answer would be 0.3 * 15 = 4.5
That would be 1925 ( 15 + 05 = 19 and 10 + 15 = 25)
Answer:
Step-by-step explanation:
The vertical component of the initial launch can be found using basic trigonometry. In any right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. Let the vertical component at launch be . The magnitude of will be the hypotenuse, and the relevant angle is the angle to the horizontal at launch. Since we're given that the angle of elevation is , we have:
(Recall that )
Now that we've found the vertical component of the velocity and launch, we can use kinematics equation to solve this problem, where is final and initial velocity, respectively, is acceleration, and is distance travelled. The only acceleration is acceleration due to gravity, which is approximately . However, since the projectile is moving up and gravity is pulling down, acceleration should be negative, represent the direction of the acceleration.
What we know:
Solving for :
Answer:
Step-by-step explanation:
(3x+1)(x-3)-(2-2x^2-3x)
3x^2+x-9x-3-2+2x^2+3x
3x^2+2x^2+x-9x+3x-3-2
5x^2-5x-5
the constant term in the simplified expression is -5.
Answer:
122.5 lbs
Step-by-step explanation:
The relation between force, wind speed, and area can be written ...
f = ks²a
for some wind speed s and area a.
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The constant of proportionality, k, can be found from the given data.
64.8 = k(18²)(500) . . . force in pounds, area in square feet, speed in mph
k = 64.8/(324×500) = 0.0004
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Using the equation with the second set of data, we have ...
f = 0.0004(35²)(250) = 122.5 . . . . pounds
The force on the 250 square foot sail would be 122.5 pounds.