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marta [7]
3 years ago
12

A high school soccer team is going to Columbus to see a professional soccer game. A coordinate grid is superimposed on a highway

map of Ohio. The high school is at point (2, 4) and the stadium in Columbus is at point (7, 6). One unit on the map is 3 miles. The approximate distance between the high school and the stadium to the nearest mile is Answer miles.
Mathematics
1 answer:
MrRissso [65]3 years ago
7 0

Answer:

16 miles

Step-by-step explanation:

Given that :

1 unit = 3 miles

High School = (2, 4)

Stadium = (7, 6)

Approximate distance between high school and stadium :

Distance between High school and Stadium

x1 = 2 ; y1= 4 ; x2 = 7 ; y2 = 6

Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)

Distance = sqrt((7 - 2)^2 + (6 - 4)^2)

Distance = sqrt((5^2 + 2^2))

Distance = sqrt(25 + 4)

Distance =5.3851648 units

1 unit = 3 miles

Approximate Distance in miles :

3 * 5.3851648 = 16.155494

Approximate distance = 16 miles

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(x+1)(x-1)^3(x-2)^3 <-- not too sure about this one, google definition of multiplicity?

Hope I helped :)
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3 years ago
Hank has eight action figures this is 12 less than the quotient of 60 and the number figures palo has
Maru [420]

Answer:

<em>6</em>

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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8 0
3 years ago
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What is 24:4 in lowest terms
pashok25 [27]

24:4 in lowest terms would be 6:1

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PLEASE HELP I AM SO CONFUSED
Natasha2012 [34]

Answer:

a)  h(3) = 9

b)  h(0) = 6

c)  h(6) = 4

Step-by-step explanation:

Piecewise functions have <u>multiple pieces</u> of curves/lines where each piece corresponds to its definition over an <u>interval</u>.

Given piecewise function:

\sf h(x)=\begin{cases}\sf \dfrac{x^2-36}{x-6} &\textsf{if }x\neq  6\\\\\sf 4 & \textsf{if }x=6\end{cases}

Therefore, the function has two definitions:

  \sf h(x)=\dfrac{x^2-36}{x-6} \quad \textsf{when x does not equal 6}

  \sf h(x)=4 \quad \textsf{when x equals 6}

<u>Part (a)</u>

h(3) means to substitute x = 3 into the function.

As <u>x does not equal 6</u>, substitute x = 3 into the <u>first piece of the function</u>:

\begin{aligned}\sf \implies h(3) & =\sf \dfrac{(3)^2-36}{(3)-6}\\\\ & = \sf \dfrac{9-36}{-3}\\\\ & = \sf \dfrac{-27}{-3}\\\\ & = \sf 9\end{aligned}

<u>Part (b)</u>

h(0) means to substitute x = 0 into the function.

As <u>x does not equal 6</u>, substitute x = 0 into the <u>first piece of the function</u>:

\begin{aligned}\sf \implies h(0) & =\sf \dfrac{(0)^2-36}{(0)-6}\\\\ & = \sf \dfrac{0-36}{-6}\\\\ & = \sf \dfrac{-36}{-6}\\\\ & = \sf 6\end{aligned}

<u>Part (c)</u>

h(6) means to substitute x = 6 into the function.

As <u>x equals 6</u>, then use the <u>second piece of the function</u>:

\sf \implies h(6)=4

Learn more about piecewise functions here:

brainly.com/question/11562909

brainly.com/question/28151925

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