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3 years ago

Find the number of each kind of atom2MgO

2 answers:

4 0

2Mg+O squared→2MgO ((when I say squared it means u need to put that little 2 underneath the O if ur still confused I can help u a little more :)

gizmo_the_mogwai [7]3 years ago

3 0

Answer:

2016

Step-by-step explanation:

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Why is 59.47 > 59.3?

Charra [1.4K]

Because .4 is bigger than .3.

the closer you are to .9 the more closer you are to a positive 1

hope this helps :)

8 0

3 years ago

Read 2 more answers

A student has four sticks of wood that measures 3 inches, 4 inches, 5 inches, and 6 inches.Can the student use any three of thes

saw5 [17]

Answer:

Yes, the student can use three of these sticks to make a right triangle.

Step-by-step explanation:

The measure of four sticks = 3 inches, 4 inches, 5 inches and 6 inches.

Now, in a right angled triangle, by PYTHAGORAS THEOREM the three sides of the triangle base, perpendicular and hypotenuse are in the given following relation :

$(Base)^{2} + (Perpendicular)^{2} = (Hypotenuse)^{2}$

Now, here among all four sticks

$(3)^{2} +(4)^{2} = 9 + 16 = 25$

and $25 = (5)^{2}$

So, there exists three sticks of length 3 in, 4 in and 5 inches which satisft Pythagoras Theorem , such that:

$(3)^{2} + (4)^{2} = (5)^{2}$

So, the required length sticks are 3 inches, 4 inches and 5 inches.

Hence, the student use three of these sticks to make a right triangle.

5 0

3 years ago

Compare the perimeters of the two regular figures. Which statement is true?

adell [148]

Answer:

(A). The perimeter of the octagon is greater than that of the hexagon.

Step-by-step explanation:

Since, hexagon consists of 6 sides and 6 angles, thus the measure of one angle of the hexagon will be= $\frac{(n-2){\timeS}180^{\circ}}{6}$

= $\frac{(6-2){\timeS}180^{\circ}}{6}$

= $\frac{(4){\timeS}180^{\circ}}{6}$

= $120^{\circ}$

Now, since MQ is the angle bisector of the one of the angle of the hexagon, therefore ∠QMP=60°.

Now, from ΔQMP. we have

$\frac{MP}{MQ}=cos60^{\circ}$

$MP=\frac{1}{2}$

Thus, the perimeter of the hexagon is:

$P=12{\times}MP$

$P=12{\times}\frac{1}{2}$

$P=6 units$

Thus, the perimeter of hexagon is 6 units.

Also, Since, octagon consists of 8 sides and 8 angles, thus the measure of one angle of the octagon will be= $\frac{(n-2){\timeS}180^{\circ}}{8}$

= $\frac{(8-2){\timeS}180^{\circ}}{8}$

= $\frac{(6){\timeS}180^{\circ}}{8}$

= $135^{\circ}$

Now, since AP is the angle bisector of the one of the angle of the octagon, therefore ${\angle}PAC=cos\frac{135}{2}$ .

From ΔAPC, we have

$AC=cos\frac{135}{2}$

Now, Perimeter of octagon is:

$P=16{\times}cos\frac{135}{2}$

$P=16{\times}0.382$

$P=6.122 units$

Thus, the perimeter of octagon is 6.122 units.

Now, the perimeter of octagon is greater than perimeter of the hexagon, thus option A is correct that is The perimeter of the octagon is greater than that of the hexagon.

4 0

3 years ago

A car used 15 gallons of gasoline and traveled a total distance of 350 miles. The car's fuel efficiency is 25 miles per gallon o

stepan [7]

The equation would be letter b. 25h + 20 (15 - h) = 350
Let’s try to solve to get the value of h
=> 25h + 20(15 -h) = 350
=> 25h + (300 – 20h) = 350
=> 25h + 300 – 20h = 350
=> 300 + 5h = 350
=> 5h = 350 – 300
=> 5h / 5 = 50/ 5
=> h = 10
Thus the value of h is 10 which means a car travel on the highways and used 10 gallons of gasoline,

3 0

3 years ago

Square root3(square root3+2square root12) simplify it.Answer should be square root 3.

julsineya [31]

Answer:

sqrt3[sqrt3+2sqrt12]=sqrt3[sqrt3+4sqrt3] = sqrt3[5sqrt3= 3x5 =15

5 0

2 years ago

Read 2 more answers

Find the number of each kind of atom2MgO​

Find the number of each kind of atom2MgO