C(p) = 175 + 3.5p
Substitute for p = 125
C(p) = 175 + 3.5(125)
C(p) = 175 + 437.5
C(p) = 612.5
So, your final answer is Six hundred twelve dollars and 5 cents.
Hope it helped.
9514 1404 393
Answer:
(c) 1.649
Step-by-step explanation:
For a lot of these summation problems it is worthwhile to learn to use a calculator or spreadsheet to do the arithmetic. Here, the ends of the intervals are 1 unit apart, so we only need to evaluate the function for integer values of x.
Almost any of these numerical integration methods involve some sort of weighted sum. For <em>trapezoidal</em> integration, the weights of all of the middle function values are 1. The weights of the first and last function values are 1/2. The weighted sum is multiplied by the interval width, which is 1 for this problem.
The area by trapezoidal integration is about 1.649 square units.
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In the attached, we have shown the calculation both by computing the area of each trapezoid (f1 does that), and by creating the weighted sum of function values.
To solve this problem, we need to know the formulas for the areas of each of these shapes. The formula for the area of a circle is πr², the area of a rectangle is b * h, the area for a square is s², and the area for a triangle is 0.5bh. Now we can solve.
1) This is a circle, so the area is πr² = π(6)² = 36<span>π square feet
2) This is a square, so the area is s</span>² = 12² = 144 square yards
3) This is a rectangle, so the area is b * h = 6 * 14 = 84 square inches
4) This is a rectangle, so the area is b * h = 7 * 3 = 21 square inches
5) This is a circle, so the area is πr² = π(4)² = 16<span>π square feet
6) This is a triangle, so the area is 0.5bh = 0.5 (8 * 8) = 0.5 * 64 = 32 yd.</span>²
7) This is a triangle, so the area is 0.5bh = 0.5 (5 * 10) = 50 * 0.5 = 25 yd.²
8) This is a rectangle, so the area is b * h = 10 * 2 = 20 in²
9) This is a square, so the area is s² = 9² = 81 ft²
Evaluate.
Exact Form:
2/3
Decimal Form:
0.6∞
Hope this helps! :)