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3 years ago

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how much money was originally invested if you have $45,917.34 in an account after 9 years of generating 7% interest compounded m

onthly

1 answer:

dsp733 years ago

5 0

Answer:

2

Step-by-step explanation:

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How do you do this equation? <br> 6- 4x less than or equal to 34

Alex73 [517]

X would be less than 6 2/3.

4 0

3 years ago

Read 2 more answers

A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin

Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

$T_1cos\theta_1-T_2cos\theta_2=0$ (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

$T_1sin\theta_1+T_2sin\theta_2-W=0$ (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

$T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2$

Then, you sum the equations:

$T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2$ (3)

Next, you use the following identity:

$sin^2\theta+cos^2\theta=1$

and you obtain in the equation (3):

$T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°$

With this values you can calculate the value of the another angle, by using the equation (1):

$\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°$

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

$l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\$

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

3 0

3 years ago

Option 1: Use Your Credit Card (15 pts)

Elza [17]

Answer:

gvxgbdgcdgcdg

Step-by-step explanation:

fd jcdnvfb x bff vfvff

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3 years ago

Im doing this problem where I have to deal with fractions that have variables in them. here is the problem. I linked the picture

AVprozaik [17]

First you should combine n/6-5n/12
that goes to 2n/12-5n/12 which equals -3n/12

then you should cross multiply -3n/12 by 1/16
12(1)=-3n(16)
12=-48n then solve for n by dividing by -48
-12/48=n simplify -1/4=n or -.25=n

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3 years ago

Amanda has an envelope that is 2 1/4 inches tall. The envelope is 4 1/3 times as long as it is tall. How long is her envelope?

Sidana [21]

Answer:

its 2 1/2 its width

Step-by-step explanation:

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3 years ago