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Debora [2.8K]
3 years ago
7

Choose Yes or No to tell if the fraction 3 5 will make each equation true. 7 20 + □ = 19 20 Choose... □ + 3 10 = 3 15 Choose...

1 2 + 2 3 = □ Choose... 1 10 + 1 2 = □ Choose...
Mathematics
1 answer:
OleMash [197]3 years ago
4 0

Answer:

True ; false ; False ; true

Step-by-step explanation:

Equation 1:

7 20 + □ = 19 20

19 / 20 - 7/20

(19 - 7) / 20

12/ 20 = 3/5

Equation 2:

□ + 3 10 = 3 15

3/5 + 3/10

(6 + 3) / 10 = 9/10

Equation 3:

1 2 + 2 3 = □

1/ 2 + 2/3

(3 + 4) / 6

7 / 6

Equation 4:

1 10 + 1 2 = □

1/10 + 1/2

(1 + 5) / 10

6 / 10 = 3/5

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Step-by-step explanation:

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if the volume of a cube shaped box is 729 cubic inches, how many 1 inch cubes could fit along one side?
Ronch [10]

Answer:

81 1-inch cubes

Step-by-step explanation:

Cube root of 729 is 9

9 x 9 = 81

Further explanation:

A cube has 3 measures (there are all the same) to solve for the volume. If the volume is 729, and it is a cube, you would solve for the cube root, because all the numbers are the same. Then, we would get 9. Now, since a cube is made up of faces, and each one is a square, we do 9 x 9 to get the area, which is the answer, because 1-inch cubes are literally just units.

4 0
3 years ago
The 17th term of an Arithmetic sequence is 51. If the commons difference is 7, what is the first term ?
vovikov84 [41]

Answer:

The first term is:

  • a_1=-61

Step-by-step explanation:

The arithmetic sequence is defined by

a_n=a_1+\left(n-1\right)d

where

a_1 is the first term

d is the common difference

as

the 17th term of an arithmetic sequence is 51.

i.e. a_{17}=51

so

a_n=a_1+\left(n-1\right)d

a_{17}=a_1+\left(17-1\right)d        

51=a_1+\left(17-1\right)7         ∵ n = 17, a_{17}=51 , d=7

a_1+112=51                   ∵ \left(17-1\right)\cdot \:\:7=112

a_1=-61

Therefore, the first term is:

  • a_1=-61
8 0
3 years ago
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