Answer:
Check the explanation
Step-by-step explanation:
A. All polynomials of the form p(t) = a + bt2, where a and b are in: This means that A is closed under scalar mult and vector addition, and includes the zero vector.
B.All polynomials of degree exactly 4, with real coefficients: what this means is that under vector addition, B isn't closed, and it does not consist of the zero vector. What it consist of is just polynomials with degree exactly 4. Let f=x4+1f=x4+1 and let g=−x4g=−x4. Both are in B, but their sum is not, because it has degree 0.
C. All polynomials of degree at most 4, with positive coefficients: what this means is that C is not a subspace for the reason that the positive coefficients make zero vector impossible. The restriction there also makes C not closed under multiplication by the scalar −1.
So the answer is only A :D
We know that
<span>sec (theta)=1/cos (theta)
</span><span>cot (theta) = -2
cot (theta)=cos (theta)/sin (theta)
</span>cos (theta)/sin (theta)=-2----> squaring-----> cos² (theta)/sin² (theta)=4
<span>remember that
sin</span>²(theta)+cos²(theta)=1
sin² (theta)=1-cos² (theta)
substitute
cos² (theta)/[1-cos² (theta)]=4
cos² (theta)=4*[1-cos² (theta)]-----> cos² (theta)+4 cos² (theta)=4
5*cos² (theta)=4-----> cos² (theta)=4/5----> cos (theta)=2/√5
cos (theta)=(2√5)/5-----> is positive (IV quadrant)
sec (theta)=1/cos (theta)----> √5/2
the answer is
sec (theta)=√5/2
The answer is 10.5 because the equation is 2x+8=29
