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IrinaK [193]
3 years ago
15

Trig how do you do I do not know

Mathematics
1 answer:
Strike441 [17]3 years ago
7 0

9514 1404 393

Answer:

  a) 2π radians

  b) 10π inches

  c) 5/4π inches per minute

Step-by-step explanation:

The formulas are fairly straightforward. Use the given values in each.

a) θ = ωt

  θ = (π/4 radians/min)(8 min) = 2π radians

__

b) s = rθ

  s = (5 in)(2π radians) = 10π in

__

c) v = s/t

  v = (10π in)/(8 min) = 5/4π in/min

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the total attendance at a concert in a theater hall was 1500, of this total 400 were children,850 were women , and the remaining
AleksandrR [38]

<u>Answer:</u>

Below!

<u>Step-by step explanation:</u>

<u>We know that:</u>

  • 400 + 850 + m = 1500

<u>Solution of Question A:</u>

<u>Percent of children: Total children/Total attendance</u>

  • => 400/1500
  • => 4/15
  • => 0.27 (Rounded to nearest hundredth)
  • => 0.27 x 100
  • => 27%

<u>Hence, the percent of children is about 27%.</u>

<u>Solution of Question B:</u>

<u>Percent of women: Total women/Total attendance</u>

  • => 850/1500
  • => 85/150
  • => 17/30
  • => 17/30 x 100
  • => 17/3 x 10
  • => 170/3
  • => 56.67%

<u>Hence, the percent of women is 56.67%.</u>

<u>Solution of Question C:</u>

  • 400 + 850 + m = 1500
  • => 1250 + m = 1500
  • => m = 1500 - 1250
  • => m = 250

<u>Percent of men: Total men/Total attendance</u>

  • => 250/1500
  • => 1/6
  • => 0.17 (Rounded to nearest hundredth)
  • => 0.17 x 100
  • => 17%

<u>Hence, the percent of men is about 17%</u>

Hoped this helped.

BrainiacUser1357

3 0
2 years ago
A jug has a maximum capacity of 14 liters. is filled to 60% of its capacity, and then poured out at a rate of 60 mL/s. Which of
ZanzabumX [31]

Answer:

W(x) = 3.4 L - (25/1000)(L/s)*x

Step-by-step explanation:

          it a tip

W(x) = 3.4 L - (25/1000)(L/s)*x

The maximum of the jug is 4 L.

now, the jug is 85% filled, then the amount of water in the jug is:

(85%/100%)*4L = 0.85*4L = 3.4L

Now, we pour 25 mL each second, so we could write a linear equation as:

W(x) = 3.4L - (25ml/s)*x

where x is the number of seconds that passed since the beginning,

But we want to write this in Liters, we have that:

1L = 1000mL.

Then 1mL = (1/1000) L

then we can write 25 mL as:

25m L = 25*(1/1000) L = (25/1000) L

Then we can write the equation as

W(x) = 3.4 L - (25/1000)(L/s)*x

which is the amount of water remaining in the jug after x seconds.

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