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____ [38]
3 years ago
12

Which of the following is NOT true?

Mathematics
2 answers:
worty [1.4K]3 years ago
8 0
A trapezoid is a rectangle.
Firlakuza [10]3 years ago
7 0
A trapezoid is a rectangle
You might be interested in
Celina and Richard spend a certain amount of money from their money box each month to buy plants.
Alika [10]

Answer:

Function 2 shows a greater rate of change, because Richard spends $6 each month and Celina spends $2 each month.

4 0
3 years ago
Solve 9^x + 4 = 11 for x using the change of base formula log base b of y equals log y over log b.
Sauron [17]

Answer:

If you meant 9^x+4=11, then the answer is approximately 0.866.

If you meant 9^{x+4}=11, then the answer is approximately -2.909 which looks like what you meant based on the choices.

Step-by-step explanation:

9^x+4=11

First step is to get the exponential part by itself. The part that has the variable exponent which is the 9^x term.

To do this we need to subtract 4 on both sides:

9^x=11-4

Simplify:

9^x=7

The equivalent logarithmic form is:

\log_9(7)=x

I always say to myself the logarithm is the exponent that is how I know what to put opposite the side containing the log.

Anyways if you don't have options for computing \log_b(a) in your calculator you need to use the change of base formula.

\frac{\log(7)}{\log(9)}=x

So x \approx 0.8856

I don't see this as a choice so maybe you actually meant the following equation:

9^{x+4}=11

Let's see if this is the correct interpretation.

So the exponential part is already isolated.

So we just need to put in the equivalent logarithmic form:

\log_9(11)=x+4

Now we subtract 4 on both sides:

\log_9(11)-4=x

Again if you don't have the option for computing \log_b(a) in your calculator, you will have to use the change of base formula:

\frac{\log(11)}{\log(9)}-4=x

x \approx -2.909

6 0
3 years ago
HELP. It’s LOG form. Since were out of school I forgot how I did this and it’s due so it would be a life saver.
____ [38]

Answer:

see below

Step-by-step explanation:

exponent to log: a^b = c ---> logₐc = b

ie. question 6

log ₁₀(3x+1) = 2 -----> 10^{2} = 3x+1

that will get you through questions 1 to 3, 5 to 6, and 8

in question 4, all you have to do is know that 2^2 = 4 and 2^3 = 8, by setting the bases equal, you can manipulate the exponents to get 2x+8 = 3x-3

for questions 7 and 9,

remember that:

logₐc + logₐd = logₐ(cd)

logₐc - logₐd = logₐ(\frac{c}{d})

remember change of base is log_{a} b = \frac{log_xb}{log_xa}, this will be useful if you need your calculator since calculators only have base 10 and maybe if your calculator is good enough natural base e

4 0
3 years ago
ur a HS photographer taking pictures fir 2 classes of 21 students each. on average, each individual pic takes 3 minutes and a cl
goblinko [34]
2 classes of 21 students each
21 × 2 classes = 42 students in total
42 × 3 mins = 126 minutes for 42 students
10 mins for 2 class pics = 20 minutes
126 + 20 = 146 minutes = 2 hours and 26 minutes

It should take 146 minutes (2 hours and 26 minutes) to take all the pictures.
6 0
3 years ago
HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!<br> Show your work
cestrela7 [59]
Well start with reflecting abc over the y axis
7 0
3 years ago
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