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pychu [463]
3 years ago
11

A 50-gallon tank is filled with a 40% ethanol solution. How much solution should be drained but and replaced with an 80% ethanol

solution to increase it to a 45% solution
Mathematics
1 answer:
DIA [1.3K]3 years ago
3 0

How do you create your equations when working on a mixture word problem?

Let's try to think about the general form of a word problem involving mixtures.

In general, we have the following scenario:

a merchant sells two kinds of products (coffee, sweets, etc).

we know the unit prices for both kinds of products and for the final mixture

p

1

US dollars per pound for the first kind of product,

p

2

US dollars per pound for the second kind of product

p

m

US dollars per pound for the mixture

we know the total quantity formed by the mixture of the two products (

q

pounds)

we have to find out the quantities of each product needed to form the mixture

(here we have the variables:

x

denoting the quantity of the first kind of product and

y

denoting the quantity of the second kind of product)

Now, we have sufficient information to work out the equations.

First, we know that the sum of the two quantities is

q

pounds, which gives us the first equation:

x

+

y

=

q

Second, we know that the sale price is the product of quantity and unit price, which gives us the second equation:

p

1

x

+

p

2

y

=

p

m

⋅

q

Now, we have a system of two linear equations that can be easily solved by substitution.

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olga2289 [7]

So what they are telling you is that 5 is three higher than the variable n.
So n = 5-3 
so n is 2. 
4 0
4 years ago
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inessss [21]
Energy in the form of HEAT 
8 0
3 years ago
ILL GIVE BRAINLIEST!!!!!!<br><br> Please explain!! Thank you!!
Bumek [7]

Answer:

The answer would be C

Step-by-step explanation:

He started at 250 lbs. He is losing 3 lbs every week.

So it would be y=250(beginning weight)-3x(how much he's losing every week)

Hope this helped :)

4 0
3 years ago
Read 2 more answers
This is due today, and I have no idea what I'm doing, please help if you know anything.
defon

Binomial distribution formula: P(x) = (n  k) p^k * (1 - p)^n - k

a) Probability that four parts are defective = 0.01374

P(4 defective) = (25 4) (0.04)^4 * (0.96)^21

P(4 defective) = 0.01374

b) Probability that at least one part is defective = 0.6396

Find the probability that 0 parts are defective and subtract that probability from 1.

P(0 defective) = (25 0) (0.04)^0 * (0.96)^25

P(0 defective) = 0.3604

1 - 0.3604 = 0.6396

c) Probability that 25 parts are defective = approximately 0

P(25 defective) = (25 25) (0.04)^25 * (0.96)^0

P(25 defective) = approximately 0

d) Probability that at most 1 part is defective = 0.7358

Find the probability that 0 and 1 parts are defective and add them together.

P(0 defective) = 0.3604 (from above)

P(1 defective) = (25 1) (0.04)^1 * (0.96)^24

P(1 defective) = 0.3754

P(at most 1 defective) = 0.3604 + 0.3754 = 0.7358

e) Mean = 1 | Standard Deviation = 0.9798

mean = n * p

mean = 25 * 0.04 = 1

stdev = \sqrt{np(1-p)}

stdev = \sqrt{(25)(0.04)(1-0.04)} = 0.9798

Hope this helps!! :)

7 0
3 years ago
Seventh grade &gt; EE.11 Probability of independent and dependent events NED
ella [17]

Step-by-step explanation:

each combination of 2 specific numbers has the same probability. there is no difference in probability between the individual numbers.

remember, a probability is always desired cases over all possible cases.

we have 4 different possible outcomes every time we spin the spinner.

to get a specific number has the probability of 1/4, because we want 1 specific outcome, and have in total 4 different possibilities.

now, we spin a second time. the probability to get a specific number is again 1/4.

but, if we consider both events to be connected, when we want to know the probability to get 2 specific numbers when spinning twice, we have to multiply the individual probabilities :

1/4 × 1/4 = 1/16

so, the probability to land first on a 5, and then secondly on a 2 is 1/16.

the same as for landing first on a 3, and then on a 5.

the same as for landing first on a 4, and then on a 4 (again).

that is because the individual spin results are independent. the result of the first spin does not impact in any way the result of the second spin (in contrary to e.g. pulling multiple cards without returning the previously pulled cards).

8 0
3 years ago
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