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VikaD [51]
2 years ago
9

In ΔBCD, the measure of ∠D=90°, BD = 20, CB = 29, and DC = 21. What is the value of the cosine of ∠C to the nearest hundredth?

Mathematics
1 answer:
Romashka-Z-Leto [24]2 years ago
8 0

Step-by-step explanation:

This is what the triangle should look like, when you draw it.

As its a right-angle triangle, trigonometry was used.

Let theta represent the angle of cosine C

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\frac{originl \: value - new \: value}{originl \: value}  \times 100\%

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Hope it helps!
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