The standard equation for the circle is:
(x-h)^2+(y-k)^2=r^2, where (h,k) is the center of the circle and r is the radius.
We are given that the center is (5,1) and r=10 so
(x-5)^2+(y-1)^2=100
Answer:
Whelan
Step-by-step explanation:
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Answer:
Wow!!! you in college or some that $h!t looks hard
Step-by-step explanation:
Can u help me plz?
Answer:
1. To eliminate x-term, multiply the second by -2
2. To eliminate y-term, multiply the second by 3
Step-by-step explanation:
4x - 9y = 7 (1)
-2x + 3y = 4 (2)
1. To eliminate x-term, multiply the second by -2
-2x + 3y = 4 (2) × 2
-4x + 6y = 8 (3)
4x - 9y = 7 (1)
Add (3) and (1)
6y - 9y = 8 + 7
-3y = 15
y = 15/-3
y = -5
4x - 9y = 7 (1)
4x - 9(-5) = 7
4x + 45 = 7
4x = 7 - 45
4x = -38
x = -38/4
x = -9.5
4x - 9y = 7 (1)
-2x + 3y = 4 (2)
2. To eliminate y-term, multiply the second by 3
-2x + 3y = 4 (2) × 3
-6x + 9y = 12 (3)
4x - 9y = 7 (1)
-6x + 4x = 12 + 7
-2x = 19
x = 19/-2
x = -9.5
4x - 9y = 7 (1)
4(-9.5) - 9y = 7
-38 - 9y = 7
-38 - 7 = 9y
-45 = 9y
y = -45/9
y = -5
The second one because domain refers to x, and since at (-3,-4) the point is hollow, the sign should be < without the line under it
