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3 years ago

What is 1+1= ? and how do you do it? also what is the pendas mean?

Mathematics

1 answer:

skad [1K]3 years ago

7 0

Answer:

2, PEMDAS means parentheses, exponents, multiplication, division, addition, and subtraction.

Step-by-step explanation:

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Marcus can read about 40 pages in one hour. if he reads at the same rate for 2 hours, how many pages will marcus read?

AleksandrR [38]

Marcus will read 80 pages in 2 hours.

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3 years ago

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Six million and five thousandths

noname [10]

Answer:

6,000,000.005

Step-by-step explanation:

The correct answer in [standard form] is 6,500,000

one million= 1,000,000

six million= 6,000,000

one thousandth= .001

five thousandth= .005

6,000,000.005

Word Form: Six million and five thousandth

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3 years ago

50 points hurry 150 times 586 do the math

galben [10]

Hello,

150 x 586 equals 87,900.

Hope this helps!

May

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3 years ago

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An automobile dealership has found that for every 80 cars sold 24 will be brought back to the dealer for major repairs. If the d

Nat2105 [25]

560 divided by 80 = 7
for every 80 there are 24 cars brought back. So i know now there are 7, "80" in 560 so.

24 *7
168

168 vehicles will be brought back

4 0

3 years ago

ASAP! I NEED THIS DONE AS QUICKLY AS POSSIBLE WITH WORKING OUT

Elza [17]

Answer:

See explanation.

Step-by-step explanation:

Let us first analyze some principle theory. By definition we know that the velocity ( $v$ ) is a function of a distance ( $d$ ) covered in some time ( $t$ ), whilst acceleration ( $a$ ) is the velocity achieved in some time. These can also been expressed as:

$v = \frac{d}{t}\\$ and $a=\frac{v}{t}$

We also know that both velocity and acceleration are vectors (therefore they are characterized by both a magnitude and a direction). Finally we know that given a position vector we can find the velocity and the acceleration, by differentiating the vector with respect to time, once and twice, respectively.

Let us now solve our problem. Here we are givine the Position vector of a particle P (in two dimensional space of $i-j$ ) as:

$r=(3t^3-t+3)i+(2t^2+2t-1)j$ Eqn.(1)

Let us solve.

Part (a) Velocity: we need to differentiate Eqn.(1) with respect to time as:

$v(t)=\frac{dr}{dt}\\\\ v(t)=[(3)3t^2-1]i+[(2)2t+2]j\\\\v(t)=(9t^2-1)i+(4t+2)j$ Eqn.(2)

Part (b) Acceleration: we need to differentiate Eqn.(2) with respect to time as:

$a(t)=\frac{dv}{dt}\\ \\a(t)=[(2)9t]i+4j\\\\a(t)=(18t)i+4j$

Thus the expressions for the velocity and the acceleration of particle P in terms of t are

$v(t)=(9t^2-1)i+(4t+2)j$ and $a(t)=(18t)i+4j$

6 0

4 years ago