Absolute value is like how far from 0.
For example. -5 is 5 units away from 0. We can use the absolute value symbol to determine that the value is far away from 0 in how many units.
So the answer is C or the third one.
Answer:![\frac{8}{3}\times \sqrt{\frac{2}{5}}](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B3%7D%5Ctimes%20%5Csqrt%7B%5Cfrac%7B2%7D%7B5%7D%7D)
Step-by-step explanation:
Given two upward facing parabolas with equations
![y=6x^2 & y=x^2+2](https://tex.z-dn.net/?f=y%3D6x%5E2%20%26%20y%3Dx%5E2%2B2)
The two intersect at
![6x^2=x^2+2](https://tex.z-dn.net/?f=6x%5E2%3Dx%5E2%2B2)
![5x^2=2](https://tex.z-dn.net/?f=5x%5E2%3D2)
=![\frac{2}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D)
x=![\pm \sqrt{\frac{2}{5}}](https://tex.z-dn.net/?f=%5Cpm%20%5Csqrt%7B%5Cfrac%7B2%7D%7B5%7D%7D)
area enclosed by them is given by
A=![\int_{-\sqrt{\frac{2}{5}}}^{\sqrt{\frac{2}{5}}}\left [ \left ( x^2+2\right )-\left ( 6x^2\right ) \right ]dx](https://tex.z-dn.net/?f=%5Cint_%7B-%5Csqrt%7B%5Cfrac%7B2%7D%7B5%7D%7D%7D%5E%7B%5Csqrt%7B%5Cfrac%7B2%7D%7B5%7D%7D%7D%5Cleft%20%5B%20%5Cleft%20%28%20x%5E2%2B2%5Cright%20%29-%5Cleft%20%28%206x%5E2%5Cright%20%29%20%5Cright%20%5Ddx)
A=![\int_{\sqrt{-\frac{2}{5}}}^{\sqrt{\frac{2}{5}}}\left ( 2-5x^2\right )dx](https://tex.z-dn.net/?f=%5Cint_%7B%5Csqrt%7B-%5Cfrac%7B2%7D%7B5%7D%7D%7D%5E%7B%5Csqrt%7B%5Cfrac%7B2%7D%7B5%7D%7D%7D%5Cleft%20%28%202-5x%5E2%5Cright%20%29dx)
A=
A=![\frac{8}{3}\times \sqrt{\frac{2}{5}}](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B3%7D%5Ctimes%20%5Csqrt%7B%5Cfrac%7B2%7D%7B5%7D%7D)
Answer:
A:An inverse matrix is always a square matrix.
Step-by-step explanation:
Hopefully this helps!
Answer:
<h2>The equation represents an ellipse with an eccentricity of 0.7.</h2>
Step-by-step explanation:
The given equation is
![r=\frac{2.1}{1+0.7cos\theta}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B2.1%7D%7B1%2B0.7cos%5Ctheta%7D)
This equations represents a conic section in polar form, where the coefficient of the cosine function is the eccentricity of the conic section.
So, in this case, the eccentricity is
, which indicates that the equation belong to an ellipse, because the eccentricy of ellipses are between 0 and 1.
Therefore, the equation represents an ellipse with an eccentricity of 0.7.