Answer:
B) A worm that lives inside a bear.
Explanation:
A parasite is a living organism that lives inside or outside of another organism called a HOST in order to obtain nourishment from such organism. A parasite that lives inside its host is called ENDOPARASITE while a parasite that lives outside its host is called ECTOPARASITE.
In this question, a worm that lives inside a bear is a PARASITE because it is living inside the bear, which is the host in order to obtain nourishments. Note that, the answer is not option D because the bear is a HOST not a parasite.
The right answer is NADP+.
Ferredoxin is an iron-sulfur protein that effects electron transfer in a large number of redox reactions in cell metabolism through Fe-S clusters whose iron cations oscillate between +2 (ferrous) oxidation states. and +3 (ferric). The first protein of this type was isolated in 1962 from the anaerobic bacterium Clostridium pasteurianum. A chloroplast-specific ferredoxin is involved in the cyclic and noncyclic photophosphorylation reactions of photosynthesis. In non-cyclic photophosphorylation, ferredoxin is the ultimate electron acceptor and reduces NADP + under the action of ferredoxin-NADP + reductase (EC 1.18.1.2) with FAD and a flavin group as cofactors:
2 ferredoxin- [Fe (2+) Fe (3+) S2 (-2)] + NADP (+) + H (+) ==> 2 ferredoxin- [Fe3 (+2) S2 (-2)] + NADPH .
Answer: cumulus
Explain: cumulus clouds are clouds with flat bases are often described as puffy, cotton-like, or fluffy on appearance.
Cumulus clouds often precursors of other types of clouds, such as cumulonimbus, when influenced by weather factors such as instability, moisture, and temperature gradient.
Answer:
See the answer below
Explanation:
a) The mode of inheritance of the bar mutant is X-linked and dominant.
Assuming that barness is represented by the allele B.
Bar female =
or 
Wild type male = 
Bar female x wild type male:
x 
All of the F1 flies are bar because a single B allele is required for the trait to be expressed.
Bar male x wildtype female
x 

All the female offspring are barred while all the males are wildtype barred resulting in a 50/50 (857/905 is approximately 50/50) ratio of barred/wildtype offspring.
b) Genotypes of each of the cross above, including the parents and the F1 generations.
1.
x 
2.
x 
