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3 years ago

Which equation represents a line that passes through (–9, –3) and has a slope of –6?

Mathematics

2 answers:

Helen [10]3 years ago

3 0

Answer:

y+3= -6(x+9) is the answer

Step-by-step explanation:

dem82 [27]3 years ago

3 0

Answer:

$y+3=-6(x+9)$

Step-by-step explanation:

We are given that

Slope of a line=-6

Given point =(-9,-3)

We have to find the equation which represents the line.

The equation of line passing through the given point $(x_1,y_1)$ with slope m is given by

$y-y_1=m(x-x_1)$

Substitute the values then we get

The equation of line passing through the point (-9,-3) with slope -6 is given by

$y-(-3)=-6(x-(-9))$

$y+3=-6(x+9)$

Hence, the equation of line that passes through (-9,-3) and has a slope -6 is given by

$y+3=-6(x+9)$

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valkas [14]

Answer:

the answer is 83 degrees

Step-by-step explanation:

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2 years ago

Solve for the unknown variable: -8m - 9 = 39

Lemur [1.5K]

Answer:

m =-6

Step-by-step explanation:

To solve for the unknown variable, m, we have to get m by itself. Perform the opposite of what is being done to the equation.

-8m-9=39

9 is being subtracted from-8m, so add 9 to both sides. Addition is the opposite of subtraction.

-8m-9+9=39+9

-8m=39+9

-8m=48

-8 and m are being multiplied. Divide both sides by -8, because division is the opposite of multiplication

-8m/-8=48/-8

m=48/-8

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6 0

3 years ago

Read 2 more answers

Matthew invested $3,000 into two accounts. One account paid 3% interest and the other paid 8% interest. He earned 4% interest on

boyakko [2]

Answer:

Mathew invested $600 and $2400 in each account.

Solution:

From question, the total amount invested by Mathew is $3000. Let p = $3000.

Mathew has invested the total amount $3000 in two accounts. Let us consider the amount invested in first account as ‘P’

So, the amount invested in second account = 3000 – P

Step 1:

Given that Mathew has paid 3% interest in first account .Let us calculate the simple interest $(I_1)$ earned in first account for one year,

$\text {simple interest}=\frac{\text {pnr}}{100}$

Where

p = amount invested in first account

n = number of years

r = rate of interest

hence, by using above equation we get $(I_1)$ as,

$I_{1}=\frac{P \times 1 \times 3}{100}$ ----- eqn 1

Step 2:

Mathew has paid 8% interest in second account. Let us calculate the simple interest $(I_2)$ earned in second account,

$I_{2} = \frac{(3000-P) \times 1 \times 8}{100} \text { ------ eqn } 2$

Step 3:

Mathew has earned 4% interest on total investment of $3000. Let us calculate the total simple interest (I)

$I = \frac{3000 \times 1 \times 4}{100} ----- eqn 3$

Step 4:

Total simple interest = simple interest on first account + simple interest on second account.

Hence we get,

$I = I_1+ I_2 ---- eqn 4$

By substituting eqn 1 , 2, 3 in eqn 4

$\frac{3000 \times 1 \times 4}{100} = \frac{P \times 1 \times 3}{100} + \frac{(3000-P) \times 1 \times 8}{100}$

$\frac{12000}{100} = \frac{3 P}{100} + \frac{(24000-8 P)}{100}$

12000=3P + 24000 - 8P

5P = 12000

P = 2400

Thus, the value of the variable ‘P’ is 2400

Hence, the amount invested in first account = p = 2400

The amount invested in second account = 3000 – p = 3000 – 2400 = 600

Hence, Mathew invested $600 and $2400 in each account.

3 0

3 years ago

Read 2 more answers

In order to test for the significance of a regression model involving 3 independent variables and 47 observations, the numerator

matrenka [14]

Answer:

The correct option is C

Step-by-step explanation:

From the question we are told that

The number of independent variables is $n = 3$

The number of observation is $z = 47$

Since n is are independent variables then their degree of freedom is 3

The denominator(i.e z) degrees of freedom is evaluated as

$Df(z) = z - (n +1)$

$Df(z) = 47 - (3 +1)$

$Df(z) = 43$

So for the numerator (n) the degree of freedom is Df(n) = 3

So for the denominator(i.e z) the degree of freedom is Df(z) = 43

4 0

3 years ago

What is 4.2e+16 written out?

worty [1.4K]

42000000000000000

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4 0

3 years ago