<u>On the first part, just replace the variables with the given number to check. </u>
1) 34 + 12 = 46 → <u>Correct</u>
2) 22 - 9 = 14 → <u>Incorrect</u>
3) 6 * 9 = 54 → <u>Correct</u>
4) 39 ^ 3 = 13 → <u>Correct</u>
<u />
<u>On the second part, simply change the symbols. Like this:</u>
5) 7 + k = 11 ⇒ 11 - 9 = k
<u>K = 2 </u>
6) p - 24 = 13 ⇒ 13 + 24 = p
<u> p = 37 </u>
7) b - 16 = 7 ⇒ 7 + 16 = b
<u>b = 23</u>
8) 
+ m = 
⇒ - = m
<u>m = 13/30</u>
<u></u>
<em><u>Hope this helps!</u></em>
If one sound is 10^x times more intense than another sound, then it has a sound level which is 10*x more decibels than the less intense sound. So, 10*6=60=7.75^2≈60
The battle of the Alamo is a long-recognized symbol of bravery in the face of unbeatable odds. Although the battle itself lasted only 90 minutes, it was the culmination of a 13-day siege by General Antonio López de Santa Anna's troops against the outnumbered inhabitants of the fort.
Answer: 
Step-by-step explanation:
<em>Thus, the expressions will be used: (5x² + 15x - 20) and (x + 4).</em>
<em>Let's check:</em>
Let the first brother = x
second brother = x + 2
third brother = x + 4
<span>The product of the first and third boys' ages is 20 more than twice the second boy's age:
x(x+4) = 2(x+2) + 20
x</span>² + 4x = 2x + 4 + 20
x² + 4x - 2x - 24 = 0
x² + 2x - 24 = 0
(x - 4)(x + 6) = 0
x = 4 or -6 (rejected, age cannot be negative)
First brother = 4
Second brother = 4 + 2 = 6
Third brother = 4 + 4 = 8
The three boys are 4, 6, and 8 years old.
