The width of the path is 4 meters.
<h3>How to find the width of the path?</h3>
The pool is measuring 8 meters by 26 meters is surrounded by a path of uniform width.
The area of the pool and the path combined is 544 square meters.
Therefore, The dimensions of pool are 8 meters and 26 meters as it is surrounded by a path of uniform width, let the width be x meters and
the dimensions of the pool and the path combined will be
8 + 2x and 26 + 2x and as area is 544 m²
, the equation is
(8 + 2x)(26 + 2x) = 544
208 + 16x + 52x + 4x² = 544
4x² + 68x - 544 + 208 = 0
4x² + 68x - 336 = 0
4(x² + 17x - 84) = 0
x² + 17x - 84 = 0
Hence,
(x - 4)(x + 21)
Therefore,
x = 4 and x = -21
As width of path cannot be negative, it is 4 meters.
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Answer:
first one
Step-by-step explanation:
first one 10/10
2nd ome 9.6/10
I like the first one better
D
167 cm = 1.67m
1.67m = 0.167dm
D. 167/1000 = 0.167
Answer:
Infinate solutions
Step-by-step explanation:
You’d use elimination
so you’d want to get either the x values to be the same or the y values so in this case we can multiply the top equation (4x + 6y=7) by 3 and then subtract the two equations so, 3(4x+6y=7) = 12x + 18y = 21 which is the same as the other equation meaning If you subtract the two you get 0=0 which leaves you with infinite solutions.