A camp has 24 kids in total. In the main hall there were 5 boys out of 9 students in total and in the cafeteria there were 12 girl out of 15 kids in total.
Write the ratios in different formats EX: a to b, a:b, and a/b
Answer:
![x^2\sqrt[3]{x}](https://tex.z-dn.net/?f=x%5E2%5Csqrt%5B3%5D%7Bx%7D)
Step-by-step explanation:
The relevant properties of exponents are ...
(a^b)(a^c) = a^(b+c)
(a^b)^c = a^(bc)
1/a^b = a^-b
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Your expression simplifies to ...
![\displaystyle x^{\frac{6}{3}+\frac{6}{9}-\frac{1}{3}}=x^{\frac{7}{3}}\\\\=x^2\sqrt[3]{x}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%5E%7B%5Cfrac%7B6%7D%7B3%7D%2B%5Cfrac%7B6%7D%7B9%7D-%5Cfrac%7B1%7D%7B3%7D%7D%3Dx%5E%7B%5Cfrac%7B7%7D%7B3%7D%7D%5C%5C%5C%5C%3Dx%5E2%5Csqrt%5B3%5D%7Bx%7D)
If there's a constant value like k or c as well as x, then you have to set each equation equal to each other and plug in the restriction for x. So if x is less than or equal to 2, you plug in two! Then use algebra to solve for k or c!!
Answer:
The the probability both are allergic to pollen is <u>0.0289</u> and the probability at least one is allergic to pollen <u>0.3111</u>.
Step-by-step explanation:
Given:
About 17% of the population of a large country is allergic to pollen.
So we can say that;
The Probability of individual to be allergic is 0.17
P(allergic) = 0.17
P(non-allergic) = 1 - 0.17 = 0.83
If 2 people are randomly selected be and individual events.
So we can say that;
P(A∩B) = P(A) × P(B)
Now we will find the Probability that both are allergic.
1) P(Both Allergic) = P(allergic) × P(allergic) = 
2) P(at least one Allergic) = 1 - P(both non-allergic)
P(at least one Allergic) = 1 - (P(non-allergic) × P(non-allergic))
P(at least one Allergic) = 
Hence The the probability both are allergic to pollen is 0.0289 and the probability at least one is allergic to pollen 0.3111.