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olga2289 [7]
4 years ago
8

Beth ran a 400 meter

Mathematics
1 answer:
Sergeeva-Olga [200]4 years ago
8 0
So if Beth ran the 400 meter dash in 57.2 seconds, and that time was 2.4 seconds faster than her previous time, she would have run a 59.6 second previous time. The equation would be X (current time) + Y (time difference) = Z (Previous time) we can see that her current time is 57.2 seconds, so that would replace X. We now have 57.2+Y=Z. So we can see in the problem that it was 2.4 seconds faster, so that’s the time difference. Our new equation is 57.2+2.4=Z. Now all we have to do is add 57.2 and 2.4 and you get her previous time, which is 59.6 seconds. Hope this helped! :D
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Answer:

4

Step-by-step explanation:

Find the length of side FD given that

Since both triangles are similar, then

AB= FD

2x+2 = x+3

Collect like terms

2x-x =3-2

x = 1

Get FD

FD = x+3

FD = 1+3

FD = 4

Hence the measure of FD is 4

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One light-year is equal to 9,460,600,000,000 kilometers. What is this distance represented in scientific notation​
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9.4606 × 10^12

Step-by-step explanation:

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\frac{1}{4}q > -16  or \frac{q}{4} > -16

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Write out the first three terms and the last term. Then use the formula for the sum of the first n terms of an arithmetic sequen
Crank

Question:

Write out the first three terms and the last term. Then use the formula for the sum of the first n terms of an arithmetic sequence to find the indicated sum.

30

∑  (−3i+5)

i=1

Answer:

The first three terms are : 2, -1 and -4

The last term is: -85

The sum of the sequence is: -1245

Step-by-step explanation:

Given;

==================================

30

∑  (−3i+5)                    -------------------(i)

i=1

==================================

Where the ith term aₙ is given by;

a_{i} = -3i + 5         -------------------(ii)

(a) Therefore, to get the first three terms (a_1, a_2, a_3), we substitute i=1,2 and 3 into equation (ii) as follows;

a_{1} = -3(1) + 5 = 2

a_2 = -3(2) + 5 = -1

a_3 = -3(3) + 5= -4

Since the sum expression in equation (i) goes from i=1 to 30, then the last term of the sequence is when i = 30. This is given by;

a_{30} = -3(30) + 5 = -85

(b) The sum s_n of an arithmetic sequence is given by;

s_n = \frac{n}{2}[a_1 + a_n]   -----------------(iii)

Where;

n = number of terms in the sequence = 30

a_1 = first term = 2

a_n = last term = -85

Substitute the corresponding values of n, a_1 and a_n into equation (iii) as follows;

s_n = \frac{30}{2}[2 + (-85)]

s_n = 15[-83]

s_n = -1245

3 0
3 years ago
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