How would I at least start out those two problems?
It looks to me like you already did. Now just follow through with it.
If the length of each side of the frame's inner dimension (i.e. the glass) is x, and the length of each side of the frame's outer dimension is x^2 - 3, then the area of the frame is:
A = (outer dimension)^2 - (inner dimension)^2
27 = (x^2 - 3)^2 - (x)^2
27 = x^4 - 6x^2 + 9 - x^2
27 = x^4 - 7x^2 + 9 <----- This is where you got to already.
0 = x^4 - 7x^2 - 18
0 = (x^2 - 9)(x^2 + 2)
Therefore, either x^2 = 9 or x^2 = -2... and you know it can't be the latter.
Thus, x^2 = 9 and therefore x = 3. The glass is 3" on each side.
<span>Each (outer) side of the frame is x^2 - 3 = 9 - 3 = 6" </span>
Estimating is an educated guess, so 3/8 is just less than half, and 1/12 is just a bit more than 0. So you could estimate that 3/8 + 1/12 = roughly 1/2
<span> if you add 3/8 and 1/12 you get 11/24</span>
36 + 5 = 41
41 x 2 = 82
The answer is 82
Answer:
16
Step-by-step explanation:
12-(-4)=12+4=16