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2 years ago

Select the correct answer.

Mathematics

1 answer:

vladimir1956 [14]2 years ago

6 0

Answer: $\Large\boxed{A.~y=3x+4}$

Step-by-step explanation:

Given information

Slope = 3

Point = (-3, -5)

Given the format of the equation

Slope-intercept form: y = mx + b

m = Slope
b = y-intercept

Substitute values into the equation

y = (3)x + b

y = 3x + b

Substitute the given point into the equation to get the value of [ b ]

(-5) = 3(-3) + b

-5 = -9 + b

b = -5 + 9

b = 4

Therefore, the equation of the line is $\Large\boxed{y=3x+4}$

Hope this helps!! :)

Please let me know if you have any questions

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3 years ago

Read 2 more answers

Find the solution(s) for x in the equation below. x^2 + 10x + 21= 0

Law Incorporation [45]

The solutions for ‘x’ in the given equation are – 3 and - 7

Step-by-step explanation:

Given equation:

$x^{2} + 10 x + 21 = 0$

To find the ‘x’ value, try to factor, because in this case it works, it's fast. By using factor method, we get

(x + 3) (x + 7) = 0 (adding both value we get 10 and multiply as 21 as in equation and check with signs also while factoring)

x = - 3, -7

Verify above values by multiply both terms,

(x + 3) (x + 7) = 0

$x^{2} + 7 x + 3 x + 21 = 0$

$x^{2} + 10 x + 21 = 0$ (so values obtained from factor method are correct)

Or, can use quadratic formula, for $a x^{2} + b x + c=0$ , the solutions are given by:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

In the given equation, a = 1, b = 10, c = 21, apply these in above formula

$x=\frac{-10 \pm \sqrt{10^{2}-(4 \times 1 \times 21)}}{2(1)}=\frac{-10 \pm \sqrt{100-84}}{2}$

$x=\frac{-10 \pm \sqrt{16}}{2}=\frac{-10 \pm 4}{2}$

So,

When $x=\frac{-10+4}{2}=\frac{-6}{2}=-3$

When $x=\frac{-10-4}{2}=\frac{-14}{2}=-7$

Hence, the values for ‘x’ are - 3 and - 7

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Step-by-step explanation:

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Step-by-step explanation:

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