Xavier cuts a slice of pizza into two parts. One part has an angle that measures 42 degrees. The other part has an angle that me
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The amplitude of the sine wave with RMS value of 220 V is
A = 220√2 volts.
The sine waveform is
v(t) = 220√2 sin(2πft)
where
f = 50 Hz, the frequency.
The period is
T = 1/f = 1/50 = 0.02 s
Use a graphical solution (shown below) to determine the number of times that v(t) = 220 in the interval t = [0, 0.02] s.
There are 2 instances when the voltage is 220 V in the interval t =[0, 0.02] s.
Note that 1 second is an integral multiple of 0.02 seconds.
Therefore in the interval [0,1], the number of instances when v(t) = 220 V is
(1/0.02)*2 = 100
Answer: 100
A = 220√2 volts.
The sine waveform is
v(t) = 220√2 sin(2πft)
where
f = 50 Hz, the frequency.
The period is
T = 1/f = 1/50 = 0.02 s
Use a graphical solution (shown below) to determine the number of times that v(t) = 220 in the interval t = [0, 0.02] s.
There are 2 instances when the voltage is 220 V in the interval t =[0, 0.02] s.
Note that 1 second is an integral multiple of 0.02 seconds.
Therefore in the interval [0,1], the number of instances when v(t) = 220 V is
(1/0.02)*2 = 100
Answer: 100
Step-by-step explanation:
Given expression;
2x + y = -5;
The given equation must be written in a form where the slope is the negative inverse of the given one.
A line perpendicular to another will have a negative inverse slope.
2x + y = -5
Equation of a straight line is generally written as;
y = mx + c
y and x are the coordinates
m is the slope
c is y - intercept
2x + y = -5
y = -2x -5
The slope of the perpendicular =
So,
the new line;
y = x -5
Any line with slope of will be perpendicular