Answer:
At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.
Step-by-step explanation:
Hello!
Considering the dependent variable:
Y: Ductility in steel.
And the independent variable:
X: Carbon content of the steel.
The linear regression was estimated and a prediction interval was calculated.
The prediction interval is calculated to predict a value that the variable Y (response variable) can take for a given value of the variable X (predictor variable) in the definition range of the linear regression line. Symbolically [Y/X=
]
In this case 95% prediction interval for Y/X=0.5
At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.
I hope it helps!
Answer:
B
Step-by-step explanation:
Let's compare the two values of 12/16 and 3/4.
Notice that 12/16 isn't a simplified fraction; both the numerator and denominator are divisible by 4. So divide the top and bottom by 4:
12 / 4 = 3
16 / 4 = 4
We are left with:
12/16 = 3/4
Now, we see that Line A and Line B are equal in length, so the answer is B.
<em>~ an aesthetics lover</em>
Answer:
y>-5-3x
Step-by-step explanation:
Answer:
$360
Step-by-step explanation:
If the company charges $30 for $500 in one month.
The interest they will be changing for a year = 30*12 = $360 interest.
It's just simple, multipling the the interest value by 12 to get it's annual interest value.