Answer: y = -3
<u>Step-by-step explanation:</u>
-8x - 5y = -1
<u>+8x </u> <u>+8x </u>
-5y = 8x - 1
<u> ÷-5 </u> <u> ÷-5</u> <u>÷-5</u>
y = 
y(2) = 
= 
= 
= -3
4x^2-3x+4y^2+4z^2=0
here we shall proceed as follows:
x=ρcosθsinφ
y=ρsinθsinφ
z=ρcosφ
thus
4x^2-3x+4y^2+4z^2=
4(ρcosθsinφ)^2-3(ρcosθsinφ)+4(ρsinθsinφ)^2+4(ρcosφ)
but
ρ=1/4cosθsinφ
hence we shall have:
4x^2-3x+4y^2+4z^2
=1/4cosθsinθ(cosθ(4-3sinφ))+4sin^2(φ)
Answer:I'd sayb
Step-by-step explanation: