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Vaselesa [24]
3 years ago
13

Help!! I have been struggling on this!

Mathematics
1 answer:
LiRa [457]3 years ago
6 0

Answer:

B

as [tex]\cos(\theta)=\srqt{1-\sin^2(\theta)}\[tex]

and since theta is in second quadrant, where cosine is negative,

so -√(1-z²)

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