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3 years ago

Can you help me please

Mathematics

1 answer:

stellarik [79]3 years ago

8 0

Answer:

sine 23 = x/21

Multiply both sides by 21

21 x sine 23 = x

Now, use a calculator and find the answer of the 21 times the sine of 23:

x = -17.7706284876

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Which of the following describes an angle with a vertex at Z?

Tresset [83]

B is the answer and why is bc I took the quiz

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3 years ago

13. Suppose the probability of passing a driving test is 65%. (a) On a certain afternoon 15 people are tested. (i) What is the e

Alex_Xolod [135]

Answer: 9

Step-by-step explanation:

Based on the information given in the question, the expected number of people who pass will be calculated as:

= Probability of passing the driving test × Number of people tested

= 65% × 15

= 0.65 × 15

= 9.75

Therefore, expected number of people who pass is 9.

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3 years ago

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Sophie [7]

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2 years ago

Find the length of the hypotenuse. 45 degree triangle 3 square root of <br><br> 2

stira [4]

Answer:

Hypotenuse = 6

Step-by-step explanation:

Find attached diagram used in solving the question.

The triangle is a 45°-45°-90° triangle meaning it's two legs are equal. The opposite = adjacent

Since we are told to find hypotenuse, it means the length given = opposite = adjacent = 3√2

Hypotenuse ² = opposite ² + adjacent ²

Hypotenuse ² = (3√2)² + (3√2)²

Hypotenuse ² = 9(2)+9(2) = 18+18

Hypotenuse ² = 36

Hypotenuse = √36

Hypotenuse = 6

8 0

3 years ago

Find the solution of the following equation whose argument is strictly between 270^\circ270 ∘ 270, degree and 360^\circ360 ∘ 360

Natasha2012 [34]

$\rightarrow z^4=-625\\\\\rightarrow z=(-625+0i)^{\frac{1}{4}}\\\\\rightarrow x+iy=(-625+0i)^{\frac{1}{4}}\\\\ x=r \cos A\\\\y=r \sin A\\\\r \cos A=-625\\\\ r \sin A=0\\\\x^2+y^2=625^{2}\\\\r^2=625^{2}\\\\|r|=625\\\\ \tan A=\frac{0}{-625}\\\\ \tan A=0\\\\ A=\pi\\\\\rightarrow z= [625(\cos (2k \pi+pi) +i \sin (2k\pi+ \pi)]^{\frac{1}{4}}\\\\k=0,1,2,3,4,....\\\\\rightarrow z=(625)^{\frac{1}{4}}[\cos \frac{(2k \pi+pi)}{4} +i \sin \frac{(2k\pi+ \pi)}{4}]$

$\rightarrow z_{0}=(625)^{\frac{1}{4}}[\cos \frac{pi}{4} +i \sin \frac{\pi)}{4}]\\\\\rightarrow z_{1}=(625)^{\frac{1}{4}}[\cos \frac{3\pi}{4} +i \sin \frac{3\pi}{4}]\\\\ \rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]\\\\ \rightarrow z_{3}=(625)^{\frac{1}{4}}[\cos \frac{7\pi}{4} +i \sin \frac{7\pi}{4}]$

Argument of Complex number

Z=x+iy , is given by

If, x>0, y>0, Angle lies in first Quadrant.

If, x<0, y>0, Angle lies in Second Quadrant.

If, x<0, y<0, Angle lies in third Quadrant.

If, x>0, y<0, Angle lies in fourth Quadrant.

We have to find those roots among four roots whose argument is between 270° and 360°.So, that root is

$\rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]$

5 0

3 years ago

Can you help me please ​

Can you help me please