The smallest region that can be photographed is
5*7 = 35 square km
so we want to know how long it takes to zoom out to an area of
35 * 5 = 175 square km.
Notice that the length and width increase at the same rate, 2 km/sec, and they start out with a difference of two, so when the width has increased from 5 to x, the length will have increased from 7 to x+2. At the desired coverage area, then,
x(x+2) = 175
x^2 + 2x = 175
x^2 + 2x + 1 = 176 [completing the square]
(x+1)^2 = 176
x+1 = ±4√11
x = -1 ±4√11
Since a negative value for x is meaningless here, x must be
-1 + 4√11 = about 12.27 km
and the time it took to increast to that value was
(12.27 - 5) km / (2 km/sec) = about 3.63 seconds
Answer:
93.6 inch^2
Step-by-step explanation:
sides=6 side-length=6 inches Apothem= 5.2 inches Area= 6*(1/2)(6)(5.2)
Answer:4
Step-by-step explanation:
X= 2
3x= 3×2
3×2=6
6-2=4
Answer:
False
Step-by-step explanation:
-(-21) is positive 21 since there are 2 negative signs, and -21 is negative, therefore they are not the same.
Hope this helps!
Answer:
The correct option is;
(B) Yes, because sampling distributions of population proportions are modeled with a normal model.
Step-by-step explanation:
Here we have the condition for normality being that where we have a population with a given mean and standard deviation, while a sufficiently large sample is drawn from the population while being replaced, the distribution of the sample mean p will be distributed normally according to central limit theorem.