Hello there!
First of all, find the slope of the right side of the graph. The slope is 2. So far we have:
y=2
Now look at the x coordinate of the point. Now we have:
y=2|x-0|
y=2|x|
Next the graph is shifted down 2 so add a negative two.
y=2|x|-2
I hope this helps!
Best wishes.
-HuronGirl
Since PQ bisects CX at point J, JX=CJ
4y=y+9
-y -y
3y=9
divide by 3
y=3
The quadratic formula is x= -b +/- √b²-4ac / 2a
In this problem,
a=6
b=4
c=-3
Now, we can plug this into the formula:
x= -4 +/- √4²-(4)(6)(-3) / (2)(6)
x= -4 +/- √16+72 / 12
x= -4 +/- √88 /12
x= -4 +/- 2√22 /12
x= -2 +/- √22 / 6
So,
x= -2 + √22 / 6
x= -2 - √22 / 6
Please show a picture of the expressions then I could help :)
Answer: for the answer its 35 trust /%
Step-by-step explanation:
