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2 years ago

given 65,72 and 96 as the three sides of a triangle, classify it as one of the following in the picture. please help!!!!

Mathematics

1 answer:

Valentin [98]2 years ago

7 0

Answer: A) Acute

<u>Step-by-step explanation:</u>

Compare the sum of the squares of the two smaller numbers (a² + b²) to the square of the largest number (c²).

If a² + b² > c², then the triangle is Acute

If a² + b² = c², then the triangle is Right

If a² + b² < c², then the triangle is Obtuse

65² + 72² ____ 96²

4225 + 5184 ____ 9216

9409 > 9216 <em>So, the triangle is Acute</em>.

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Complete the statement using always, sometimes, or never. A rectangle is __________________ a rhombus.

Lesechka [4]

Hi!

A rectangle can sometimes be a rhombus if it has sides of all equal lengths. If a rectangle was a rhombus, it would also be a square. Furthermore, a square is always a rhombus.

Hope this helps! :)

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2 years ago

Diego is solving the equation x^2-12x = 21

uysha [10]

Answer:

The solutions to the quadratic equations will be:

$x=\sqrt{57}+6,\:x=-\sqrt{57}+6$

Step-by-step explanation:

Given the expression

$x^2-12x\:=\:21$

Let us solve the equation by completing the square

$x^2-12x\:=\:21$

Add (-6)² to both sides

$x^2-12x+\left(-6\right)^2=21+\left(-6\right)^2$

simplify

$x^2-12x+\left(-6\right)^2=57$

Apply perfect square formula: (a-b)² = a²-2ab+b²

i.e.

$x^2-12x+\left(-6\right)^2=\left(x-6\right)^2$

so the expression becomes

$\left(x-6\right)^2=57$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x-6=\sqrt{57}$

add 6 to both sides

$x-6+6=\sqrt{57}+6$

Simplify

$x=\sqrt{57}+6$

also solving

$x-6=-\sqrt{57}$

add 6 to both sides

$x-6+6=-\sqrt{57}+6$

Simplify

$x=-\sqrt{57}+6$

Therefore, the solutions to the quadratic equation will be:

$x=\sqrt{57}+6,\:x=-\sqrt{57}+6$

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2 years ago

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Effectus [21]

Answer:

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2 years ago

A=(_3 2),b (4 _6),c=(5 _10)

MAXImum [283]

First we find x of p:

$x = 2 \times ( - 3) - \frac{1}{2} \times 4 + \frac{2}{5} \times 5 \\ = - 6 - 2 + 2 = - 6$

then we find y of p:

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so

$p = \binom{ - 6}{11}$

and

$|p| = \sqrt{ {( - 6)}^{2} + {11}^{2} } \\ = \sqrt{36 + 121} = \sqrt{157} = 12.53$

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2 years ago

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KATRIN_1 [288]

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2 years ago

given 65,72 and 96 as the three sides of a triangle, classify it as one of the following in the picture. please help!!!!​

given 65,72 and 96 as the three sides of a triangle, classify it as one of the following in the picture. please help!!!!