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tia_tia [17]
2 years ago
8

Hi there I need help on this Monica wants to spend no more than $35

Mathematics
1 answer:
nikitadnepr [17]2 years ago
6 0
Need to see more instructions.
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Solve for x<br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B11%7D%7Bx%2B5%7D" id="TexFormula1" title="\frac{11}{x+5}" alt="\frac
Vika [28.1K]
The answer is X = -4/3
8 0
2 years ago
Read 2 more answers
Please help these are not easy for me
Pavel [41]

Answer:

12a^2 - 9a + 5

Step-by-step explanation:

(5a^2 - 6a - 4) - (-7a^2 + 3a - 9)

5a^2 + 7a^2 = 12a^2

-6a - 3a = -9a

-4 + 9 = 5

12a^2 - 9a + 5

7 0
3 years ago
Hey does anyone know all the numbers or just a few! It would be such a help if you do :)
wolverine [178]
(4,3) (-3,4)(-3,2)(-1,2)
8 0
2 years ago
Can someone help me with these both
Anna [14]
Hello,
so all you have to do is match the abbreviations to the triangles. The abbreviations stand for what is the SAME in both triangles, denoted by similar markings on equal sides and angles.

Abbreviations:
SSS = Side-Side-Side
SAS = Side-Angle-Side
ASA = Angle-Side-Angle
AAS = Angle-Angle-Side
HL = Hypotenuse-Leg

* Note - the angle side angle must go around the triangle in that order. ASA has the side BETWEEN the congruent angles.. SSA does NOT work.

(9.) ASA
(10.) AAS
(11.) SSS
(12.) No way to tell if congruent. (only 3 angles no side)
(13.) ASA
(14.) SAS
(15.) HL

7 0
3 years ago
Find the area each sector. Do Not round. Part 1. NO LINKS!!<br><br>​
sladkih [1.3K]

Answer:

\textsf{Area of a sector (angle in degrees)}=\dfrac{\theta}{360 \textdegree}\pi r^2

\textsf{Area of a sector (angle in radians)}=\dfrac12r^2\theta

17)  Given:

  • \theta = 240°
  • r = 16 ft

\textsf{Area of a sector}=\dfrac{240}{360}\pi \cdot 16^2=\dfrac{512}{3}\pi \textsf{ ft}^2

19)  Given:

  • \theta=\dfrac{3 \pi}{2}
  • r = 14 cm

\textsf{Area of a sector}=\dfrac12\cdot14^2 \cdot \dfrac{3\pi}{2}=147 \pi \textsf{ cm}^2

21)  Given:

  • \theta=\dfrac{ \pi}{2}
  • r = 10 mi

\textsf{Area of a sector}=\dfrac12\cdot10^2 \cdot \dfrac{\pi}{2}=25 \pi \textsf{ mi}^2

23)  Given:

  • \theta = 60°
  • r = 7 km

\textsf{Area of a sector}=\dfrac{60}{360}\pi \cdot 7^2=\dfrac{49}{6}\pi \textsf{ km}^2

3 0
2 years ago
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