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Ahat [919]
2 years ago
13

In his first 12 at bats during the baseball season, Jose had 4 hits. he maintained this hit throughout the entire season

Mathematics
1 answer:
kupik [55]2 years ago
5 0

Answer:

195

Step-by-step explanation:

If we combine the data for the two seasons, then Derek Jeter had 12 + 183 = 195 total hits in 48 + 582 = 630 total at-bats. So his overall batting average

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Let sets A and B be defined as follows.
VashaNatasha [74]
<h3>Given</h3>

  • Set A: A = {-26, -25, -24, -23, - 22, - 21}
  • Set B: B ∈ {x: x is even, x ≥ 6 and x ≤ 20}

<h3>(a) </h3>

<em />

<em>Cardinality means the number of elements in the set.</em>

Cardinality of the set A:

n(A) = 6, since we can count 6 elements.

Set B has even numbers between 6 and 20, both included:

  • B = {6, 8, 10, 12, 14, 16, 18, 20}

Then its cardinality is:

  • n(B) = 8

<h3>(b) </h3>

To solve this we need to compare the elements of sets A or B with numbers given:

  • -22 ∈ A, True       ⇒  -22 is listed as element of A
  • 6 ∈ B, True          ⇒  6 is listed as element of B
  • - 21 ∉ A, False     ⇒  - 21 is listed as element of A
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5 0
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Sin40°-sin20°/cos220°-cos200=√3​
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Step-by-step explanation:

7 0
3 years ago
Although companies would like consumers to believe that Identity theft protection is an
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The obtained answers for the given frequency distribution are:

(a) The formula for the mean in sigma notation is \bar x =\frac{1}{n}  \sum X_i where n is the number of observations; X_i are the n observations.

The mean for the given monthly plan price is $16.1.

(b) The frequency distribution for given data is {$9.99 - 2; $10 - 5; $12 - 1; $12.75 - 2; $14.99 - 6; $20 - 4; $25 - 5}

(c) The formula for the mean using the frequency distribution table is \bar x = \frac{1}{N}\sum f_ix_i where N =\sum f_i and on applying this formula for the given data, the mean is $16.1.

(d) The median for the given data is m_e = 14.99, and the mode for the given data is $14.99

<h3>What are the mean, median, and mode for a frequency distribution?</h3>

The frequency distribution has sample observations x_i and frequencies f_i.

Then, the mean is calculated by

\bar x = \frac{1}{N}\sum f_ix_i

Where N =\sum f_i (Sum of frequencies)

The median is calculated by

m_e=\left \{ {{x_{k}} \ if \ n = 2k+1 \atop {\frac{x_{k}+x_{k+1}}{2}} \ if \ n =2k} \right.

The mode is calculated by

Mode = highest frequency value

<h3>Calculation:</h3>

The given list of data is

{$14.99, $12.75, $14.99, $14.99, $9.99, $25, $25, $10, $14.99, $10, $20, $10, $20, $14.99, $10, $25, $20, $12, $14.99, $25, $25, $20, $12.75, $10, $9.99}

(a) Formula for the mean using sigma notation and use it to calculate the mean:

The formula for the mean is

\bar x =\frac{1}{n}  \sum X_i

Where n = 25; X_i - n observations

On substituting,

Mean \bar x

=1/25(14.99+12.75+14.99+14.99+9.99+25+25+10+14.99+10+20+10+20+14.99+10+25+20+12+14.99+25+25+20+12.75+10+9.99)

= 1/25(402.42)

= 16.09 ≅ 16.1

(b) Constructing a frequency distribution for the data:

Cost - frequency - cumulative frequency

$9.99 - 2 - 2

$10 - 5 - 7

$12 - 1 - 8

$12.75 - 2 - 10

$14.99 - 6 - 16

$20 - 4 - 20

$25 - 5 - 25

Sum of frequencies N = 25;

(c) Using frequency distribution, calculating the mean:

The formula for finding the mean using frequency distribution is

\bar x = \frac{1}{N}\sum f_ix_i

Where N = 25;

On substituting,

\bar x<em> </em>= 1/25 (2 × 9.99 + 5 × 10 + 1 × 12 + 2 × 12.75 + 6 × 14.99 + 4 × 20 + 5 × 25)

  = 1/25 (402.42)

  = 16.09 ≅ 16.1

Therefore, the mean is the same as the mean obtained in option (a).

(d) Calculating the median and the mode:

Since N = 25(odd) i.e., 2· 12 + 1; k = (12 + 1)th term = 13th term

So,  the median m_e = 14.99. (frequency at 13th term)

Since the highest frequency is 6 occurred by the cost is $14.99,

Mode = 14.99

Learn more about frequency distribution here:

brainly.com/question/27820465

#SPJ9

7 0
2 years ago
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