As you haven't specifically stated what exactly the question is, I will be assuming that the question is most likely asking for what the dimensions ( length and width ) of the rectangle is. With this in mind, I will be answering the question so here I go...
STEP-BY-STEP SOLUTION:
Let's solve this problem step-by-step.
Let's first establish the formula for the area of a rectangle as displayed below:
Area = Length × Width
A = lw
From this, we will establish the values for each of the parts in the area formula using the information given in the problem as displayed below:
A = 72cm^2
l = w + 6
w = w
Now, we will substitute these values into the area formula and then make ( w ) the subject as displayed below:
A = lw
72 = ( w + 6 ) ( w )
72 = w ( w + 6 )
72 = w^2 + 6w
0 = w^2 + 6w - 72
0 = w^2 + 12w - 6w - 72
0 = w ( w + 12 ) - 6 ( w + 12 )
0 = ( w + 12 ) ( w - 6 )
w + 12 = 0
w = 0 - 12
w = - 12
w - 6 = 0
w = 0 + 6
w = 6
As the answer must be positive as measurements are always positive, the answer must be the option which is a positive number.
Therefore:
w = 6
Using the equation we made for the length before, we can substitute the value of ( w ) to obtain the value of the length as displayed below:
l = w + 6
l = ( 6 ) + 6
l = 12
FINAL ANSWER:
The dimensions of the rectangle are:
Length = 12cm
Width = 6cm
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Thank you <3
Answer:
a) Interquartile range= upper quartile- lowwr quartile
= Q3- Q1
= 4.75-2.25
= 2.50
b) ( 2.5 ÷ 6 ) × 100
= 41.67%
An inertial reference frame is a frame of reference in which a body remains at rest OR moves with a constant LINEAR velocity. Answer choices A, C, and D are moving linearly at a constant rate and are all inertial frames of reference. Answer choice E is motionless, and is therefor an inertial frame of reference. Answer choice B is rotating at a constant rate. Rotation is not an inertial frame of reference.
Therefor, the answer is B.
Answer:
0.8
hope this is correct!! c:
Answer: the options that apply are
1) w(2w + 4)
5) 2w² + 4w
Step-by-step explanation:
The formula for determining the area of a rectangular garden ins expressed as
Area = length × width
The length of a garden is four more than twice its width, w. The expression for the length would be
Length = 2w + 4
Therefore, the expression that represents the area of the garden would be
w(2w + 4)
Expanding the brackets, it becomes
2w² + 4w
