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Maslowich
3 years ago
12

How many real solutions are there to the equation x2 - 7x + 12 = 0? о оооо но со

Mathematics
1 answer:
bixtya [17]3 years ago
4 0
I was butt x2-7+12=0 what
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students who failed mathematics scored the following marks 16.5,13.6,12.4,13.7 find the average mark for this students​
SSSSS [86.1K]

Answer:

16.5+13.6+12.4.17.7= 60.2

60.2÷4 =15.05

8 0
3 years ago
How would I find the mean, median and mode ?
snow_tiger [21]

Answer:

Mode is the number that occurs most often in the data set. lets say i have the numbers(6,9,2,0,3,2,1,2) it would be two because there are more two's than any other number in the data set.

Mean is found by adding all of the numbers together in the data set. you simply add your numbers together.

Median is the number that is found halfway in the data set. for example if i had the numbers (6,9,2,5,0,2,1) the median would be 5.

I hope this helps you!

8 0
3 years ago
Linda purchase a prepaid phone card for $30. Long distance calls cost $.17 a minute using this card when do use her card. Linda
balandron [24]

Answer: her call lasted for 44 minutes

Step-by-step explanation:

Linda purchase a prepaid phone card for $30. This means that the credit on her card is $30.

Long distance calls cost $0.17 each. Linda use her card only to make a long distance call. Assuming she made a total of x minutes of long distance calls, the cost would be $0.17x. The amount remaining on her card will be

30 - 0.17x

if the remaining credit on her card is $22.52, the number of minutes,x that the call lasted will be

22.52 = 30 - 0.17x

0.17x = 30 - 22.52

0.17x = 7.48

x = 7.48/0.17 = 44

7 0
3 years ago
Write 10 12/5 as an equivalent improper fraction
romanna [79]
10 \frac{12}{5} = \frac{(10 X 5 ) + 12}{5} 
= \frac{62}{5}
8 0
3 years ago
If sinA=√3-1/2√2,then prove that cos2A=√3/2 prove that
Ivan

Answer:

\boxed{\sf cos2A =\dfrac{\sqrt3}{2}}

Step-by-step explanation:

Here we are given that the value of sinA is √3-1/2√2 , and we need to prove that the value of cos2A is √3/2 .

<u>Given</u><u> </u><u>:</u><u>-</u>

• \sf\implies sinA =\dfrac{\sqrt3-1}{2\sqrt2}

<u>To</u><u> </u><u>Prove</u><u> </u><u>:</u><u>-</u><u> </u>

•\sf\implies cos2A =\dfrac{\sqrt3}{2}

<u>Proof </u><u>:</u><u>-</u><u> </u>

We know that ,

\sf\implies cos2A = 1 - 2sin^2A

Therefore , here substituting the value of sinA , we have ,

\sf\implies cos2A = 1 - 2\bigg( \dfrac{\sqrt3-1}{2\sqrt2}\bigg)^2

Simplify the whole square ,

\sf\implies cos2A = 1 -2\times \dfrac{ 3 +1-2\sqrt3}{8}

Add the numbers in numerator ,

\sf\implies cos2A =  1-2\times \dfrac{4-2\sqrt3}{8}

Multiply it by 2 ,

\sf\implies cos2A = 1 - \dfrac{ 4-2\sqrt3}{4}

Take out 2 common from the numerator ,

\sf\implies cos2A = 1-\dfrac{2(2-\sqrt3)}{4}

Simplify ,

\sf\implies cos2A =  1 -\dfrac{ 2-\sqrt3}{2}

Subtract the numbers ,

\sf\implies cos2A = \dfrac{ 2-2+\sqrt3}{2}

Simplify,

\sf\implies \boxed{\pink{\sf cos2A =\dfrac{\sqrt3}{2}} }

Hence Proved !

8 0
3 years ago
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