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deff fn [24]
3 years ago
15

Students record the number of minutes they read each day. The box plot shows the sumary of the results. Which statement best des

cribes the data?
Mathematics
2 answers:
devlian [24]3 years ago
8 0
Number of minutes i think
Novosadov [1.4K]3 years ago
3 0
^^yeah the number of minutes they read
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A triangle with sides 11m , 13m and 18m is a right triangle.<br> ​<br> A<br> True<br> B<br> False
Julli [10]

\bold{\huge{\pink{\underline{ Solution}}}}

\bold{\underline{ Given :-}}

  • <u>A </u><u>triangle </u><u>with </u><u>sides </u><u>11m</u><u>, </u><u> </u><u>13m </u><u>and </u><u>18m</u>

\bold{\underline{ To \: Find :-}}

  • <u>We</u><u> </u><u>have </u><u>to </u><u>check </u><u>it </u><u>whether </u><u>it </u><u>is </u><u>right </u><u>angled </u><u>triangle </u><u>or </u><u>not</u><u>? </u>

\bold{\underline{ Let's \: Begin :-}}

\sf{\red{ In \:right \:angled\ : triangle, }}

According to the Pythagoras theorem, The sum of the squares of perpendicular height and the square of the base of the triangle is equal to the square of hypotenuse that is sum of the squares of two small sides equal to the square of longest side of the triangle.

<u>We </u><u>imply</u><u> </u><u>it </u><u>in </u><u>the </u><u>given </u><u>triangle </u><u>,</u>

\sf{\red{ ( Perpendicular)² + (Base)² = (Hypotenuse)²}}

\sf{(AB)² + (BC)² = (AC)²}

\sf{ (11)² + (13)² = (18)² }

\sf{ 121 + 169 ≠  324 }

\sf{ 290 ≠ 324  }

<u>From </u><u>Above </u><u>we </u><u>can </u><u>conclude </u><u>that</u><u>, </u>

The sum of the squares of two small sides that is perpendicular height and base is not equal to the square of longest side that is Hypotenuse

\sf{\blue{ Hence,\: Your\: answer \:is \:false }}

5 0
2 years ago
Which expression has a value of 15 when n = 7? 43 minus 5 n 3 n minus 5 6 n minus 28 19 minus StartFraction 28 Over n EndFractio
andrey2020 [161]

Answer:

19-\dfrac{28}{n} is the expression with value of 15 when n = 7.

Step-by-step explanation:

To find the expression whose value is 15, substitute the value of n = 7 in each given expression.

Expression 1:

43-5n

Substituting the value of n,

43-5\left(7\right)

Simplifying,

43-35=8

Since the value of the expression is 8 which is not equal 15.

Hence expression 43-5n does not have value of 15 when n = 7.

Expression 2:

3n-5

Substituting the value of n,

3\left(7\right)-5

Simplifying,

21-5=16

Since the value of the expression is 16 which is not equal 15.

Hence expression 3n-5 does not have value of 15 when n = 7.

Expression 3:

6n-28

Substituting the value of n,

6\left(7\right)-28

Simplifying,

42-28=14

Since the value of the expression is 14 which is not equal 15.

Hence expression 6n-28 does not have value of 15 when n = 7.

Expression 4:

19-\dfrac{28}{n}

Substituting the value of n,

19-\dfrac{28}{7}

Simplifying,

19-4=15

Since the value of the expression is 15 which is equal 15.

Hence expression 19-\dfrac{28}{n} has the value of 15 when n = 7.

4 0
3 years ago
Read 2 more answers
The sum of the measures of two complementary angles exceeds the difference of their measure by 86º. Find the measure of each ang
katrin2010 [14]
We will translate the given statement in the problem into 
x + y  = 90 
x - y =  90 - 86 = 4 where x and y are the angles that are complementary. solving simultaneously, x = 47 degreesy = 43 degrees. 
4 0
3 years ago
I’m having a crisis so please help 7x-19&lt;16
vampirchik [111]

Answer:

5 i believe correct me if im wrong

Step-by-step explanation:

To work this problem out you would do it as if it were just a simple equation

7x-19<16 (you would first have to add 19 to both sides)

7x<35 (then you would divide by 7 to get the variable by itself)

x<5 ( you answer would then be 5)

7 0
3 years ago
What is 8 1/3% as a fraction in simplest form?
jeka94
8 1/3% would be equal to 25/4%
7 0
3 years ago
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