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3 years ago

Help Please and Thank You!

Mathematics

1 answer:

Svetllana [295]3 years ago

6 0

Step-by-step explanation:

expand the bracke

so -5(X+6) is -5x-30=15

-5x-30=15 ( add 30 so that no number in the equation) 15+30 is 45

-5x=45(divide by 5 as 45 is multiple of 5)

45/-5=-9 (positive / negative is negative)

X=-9

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In your own words, describe how to graph the linear equation y = -1/5x + 3. Step by step

Gemiola [76]

Answer:

Steps given below and graph is attached.

Step-by-step explanation:

First Step:

Find out $y-intercept$ by substituting $x=0$

$y=-\frac{1}{5}\times 0+3\\\\y=3\\\\Hence\ line\ passes\ through\ (0,3).$

Second Step:

Find out $x-intercept$ by substituting $y=0.$

$0=-\frac{1}{5}x+3\\\\\frac{1}{5}x=3\\\\x=15\\\\Hence\ line\ passes\ through\ (15,0).$

Third Step:

Draw a line passing through $(0,3)\ and\ (15,0)$ .

Graph is attached.

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3 years ago

A ball has a circumference of 9.42 what is the diameter

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3 years ago

Elle can buy 2 qt of milk for$3 or 1 gal milk for $3, which is the better deal explain.

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3 years ago

Read 2 more answers

A guy wire runs from the top of a cell tower to a metal stake in the ground. Marques places a 11-foot tall pole to support the g

astra-53 [7]

The Pythagorean theorem computed shows that the length of the guy wire, to the nearest foot, is 207 ft.

<h3>How to solve the length?</h3>

Here, we have two similar right triangles, ΔABE and ΔCDE.

CD = 11 ft

DE = 2 ft

BD = 35 ft

First, find AB:

AB/11 = (35 + 2)/2

AB/11 = 37/2

Cross multiply

AB = (37 × 11)/2

AB = 203.5 ft

Then, apply Pythagorean Theorem to find AE:

AE = √(AB² + BE²)

AE = √(203.5² + 37²)

AE = 207 ft

Therefore, the length of the guy wire is 207 ft.

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brainly.com/question/654982

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2 years ago

A bucket that weighs 5 lb and a rope of negligible weight are used to draw water from a well that is 60 ft deep. The bucket is f

mestny [16]

Answer:

The value is $W= 2640 \ ft \cdot lb$

Step-by-step explanation:

From the question we are told that

The weight of the bucket is $F = 5 lb$

The depth of the well is $x_1 = 60 \ ft$

The weight of the water is $W_w = 42 lb$

The rate at which the bucket with water is pulled is $v = 1.5 \ ft/s$

The rate of the leak is $r = 0.15 lb/s$

Generally the workdone is mathematically represented as

$W = \int\limits^{x_1}_{x_o} {G(x)} \, dx$ ]

Here G(x) is a function defining the weight of the system (water and bucket ) and it is mathematically represented as

$G(x) = F + (W_w- Ix)$

Here I is the rate of water loss in lb/ft mathematically represented as

$I = \frac{r}{v}$

=> $I = \frac{0.15 }{1.5 }$

=> $I = 0.1$

$G(x) = 5 + (42- 0.1x)$

=> $G(x) = 47- 0.1x)$

$W = \int\limits^{60}_{0} {47- 0.1x} \, dx$ ]

=> $W = [47x - \frac{0.1x^2}{2} ]|\left 60} \atop {0}} \right.$

=> $W= [47(60) - 0.05(60)^2]$

=> $W= 2640 \ ft \cdot lb$

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3 years ago