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VMariaS [17]
3 years ago
8

Crescent Company reported total sales for the current year to be $5,000,000, including cash sales of $1,000,000. Management esti

mates bad debts to be 5% of credit sales. The Allowance for Doubtful Accounts prior to adjustment has a debit balance of $20,000. The ending balance of the Allowance for Doubtful Accounts after adjustment will be: Select one: A. $170,000 B. $220,000 C. $180,000 D. $120,000
Mathematics
2 answers:
creativ13 [48]3 years ago
7 0

Answer:

i need points srry

Step-by-step explanation:

Nikolay [14]3 years ago
4 0

Answer: most likely C

Step-by-step explanation:

You might be interested in
What is the perimeter of triangle UVW
lara [203]
Count how much spaces from one point on the end of the line to the other.

Line VU has 9 units
Line VW has 12 units
Line UW has: 

a² + b² = c²
9² + 12² = c²
81 + 144 = c²
c² = 225
√c² = √225
c = 15
Line UW has: 15 units

Now add all the units together to get the perimeter:

9 + 12 + 15 = 
21 + 15 = 
36

36 is your answer

hope this helps
8 0
3 years ago
ANSWER ASAP PLEASE <br>Solve for x. 3x - 8 = 2(5 - x) <br>A) 2 <br>B) 26 <br>C) 3.6 <br>D) 13​
Ronch [10]
You gotta get x by itself so it’s C 3.6
7 0
3 years ago
Can somebody please help me with these two questions?
vovikov84 [41]
The answer to 25. is A
and 
to 26. is C (I'm not sure on this one but i think this is the answer)
6 0
3 years ago
Read 2 more answers
FAST before Mod's delete this. Plz help me share this link as I have no social media. Copy it to your clipboard fast Ctrl + C. :
Tanya [424]

Answer:

then get social media

Step-by-step explanation:

8 0
3 years ago
Determine whether the set of vectors <img src="https://tex.z-dn.net/?f=%20v_%7B1%3D%283%2C2%2C1%29%2C%20v_%7B2%7D%20%3D%28-1%2C-
Korolek [52]
Since each vector is a member of \mathbb R^3, the vectors will span \mathbb R^3 if they form a basis for \mathbb R^3, which requires that they be linearly independent of one another.

To show this, you have to establish that the only linear combination of the three vectors c_1\mathbf v_1+c_2\mathbf v_2+c_3\mathbf v_3 that gives the zero vector \mathbf0 occurs for scalars c_1=c_2=c_3=0.

c_1\begin{bmatrix}3\\2\\1\end{bmatrix}+c_2\begin{bmatrix}-1\\-2\\-4\end{bmatrix}+c_3\begin{bmatrix}1\\1\\-1\end{bmatrix}=(0,0,0)\iff\begin{bmatrix}3&-1&1\\2&-2&1\\1&-4&-1\end{bmatrix}\begin{bmatrix}c_1\\c_2\\c_3\end{bmatrix}=\begin{bmatrix}0\\0\\0\end{bmatrix}

Solving this, you'll find that c_1=c_2=c_3=0, so the vectors are indeed linearly independent, thus forming a basis for \mathbb R^3 and therefore they must span \mathbb R^3.
4 0
3 years ago
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