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Ganezh [65]
3 years ago
6

Let E = {(x, y) e R2|xy > 0}. Determine whether E is a subspace of R2 . X3

Mathematics
1 answer:
gayaneshka [121]3 years ago
5 0

Answer:

E is not a subspace of \mathbb{R}^2

Step-by-step explanation:

E is not a subspace of  \mathbb{R}^2

In order to see this, we must find two points (a,b), (c,d) in  E such that (a,b) + (c,d) is not in E.

Consider

(a,b) = (1,1)

(c,d) = (-1,-1)

It is easy to see that both (a,b) and (c,d) are in E since 1*1>0 and (1-)*(-1)>0.  

But (a,b) + (c,d) = (1-1, 1-1) = (0,0)

and (0,0) is not in E.

By the way, it can be proved that in any vector space all sub spaces must have the vector zero.

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Ayden and his children went into a grocery store and where they sell peaches for $0.75 each and mangos for $1.75 each. Ayden has
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2 years ago
What is the value of the rational expression 2x^2+5x+9/x^2+2x-1 when x=-2
Sergio039 [100]

Answer:

The value of the Rational expression when x=-2 is: -7

Step-by-step explanation:

For this exercise is important to remember:

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       (+)(+)=+\\(-)(-)=+\\(-)(+)=-

Then, given the following Rational expression:

\frac{2x^2+5x+9}{x^2+2x-1}

You need to follow these steps in order to find its value when x=-2:

1. Substitute the given value of "x" (x=2) into the expression:

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2. Evaluate and simplify:

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