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Ganezh [65]
3 years ago
6

Let E = {(x, y) e R2|xy > 0}. Determine whether E is a subspace of R2 . X3

Mathematics
1 answer:
gayaneshka [121]3 years ago
5 0

Answer:

E is not a subspace of \mathbb{R}^2

Step-by-step explanation:

E is not a subspace of  \mathbb{R}^2

In order to see this, we must find two points (a,b), (c,d) in  E such that (a,b) + (c,d) is not in E.

Consider

(a,b) = (1,1)

(c,d) = (-1,-1)

It is easy to see that both (a,b) and (c,d) are in E since 1*1>0 and (1-)*(-1)>0.  

But (a,b) + (c,d) = (1-1, 1-1) = (0,0)

and (0,0) is not in E.

By the way, it can be proved that in any vector space all sub spaces must have the vector zero.

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What is 12 divided by 6/7
Naddik [55]
What is the easiest way to divide whole numbers to fractions?
Just follow these two easy steps:
1. Multiply the whole number  to the denominator of the fraction. In other words, the bottom number of the fraction will be multiplied to the whole number, like this:

12 ÷ 6/7 = n
 <u>   6    </u>
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You will have 6/ 84.
2. Simplify.
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84= 1, 2, 3, 4, 6, 7, 12, 14, 21, 42, 84

the GCF is 6.  divide both numbers by 6, so the answer will be 1/14.

You can also get the reciprocal and proceed to multiplication , like this: (12/1 is the fractional form or the whole number 12.)
 1/12 x 6/7=n
that makes 6/84 or 1/14.
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3 years ago
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A softball team is ordering pizza to eat after their tournament. They plan to order cheese pizzas that cost $ 6 each and four-to
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