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melamori03 [73]
2 years ago
7

Please help me I’m stuck

Mathematics
1 answer:
FrozenT [24]2 years ago
8 0

Answer:

10.77 units

Step-by-step explanation:

By imaging an imaginery line at point before 1 units to be 4 units: b = 4 units

Therefore h = 11 - 1 = 10 units

Using Pythagoras theorem:

x² = h² + b²  = 10² + 4² = 100 + 16 = 116

x = √116 = 10.77 units

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three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal
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I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

=     x + x + (x + \frac{6}{5}) = \frac{27}{4}

=     3x + \frac{6}{5} = \frac{27}{4}

=     3x = \frac{27}{4} - \frac{6}{5}

( let's take the LCM of 4 and 5 = 20

=     3x = \frac{135}{20} - \frac{24}{20}

=     3x = \frac{111}{20}

=       x = \frac{111}{20} ÷ \frac{3}{1} = \frac{111}{20} × \frac{1}{3} = \frac{37}{20}

So, the weight of the equal bags are \frac{37}{20} and the weight of the third bag ( heavy one ) is \frac{37}{20} + \frac{6}{5} = \frac{37}{20} + \frac{24}{20} = \frac{61}{20}

1st bag =     \frac{37}{20} kg

2nd bag =  \frac{37}{20} kg

3rd bag =   \frac{61}{20} kg

Hope it helps...

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