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kap26 [50]
2 years ago
9

This is a simplifying question.Y+Y+Y+Y

Mathematics
2 answers:
Lostsunrise [7]2 years ago
3 0

Answer:

4y

Step-by-step explanation:

y + y + y + y = 4y

Vsevolod [243]2 years ago
3 0

Answer:

4Y

Step-by-step explanation:

In front of each Y is an invisible number 1. Therefore add, 1 + 1 + 1 + 1 to get your answer.

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3 easy questions
Tasya [4]
It is p, as x. get it?
4 0
3 years ago
Peter went to his local zoo where 50% of its exhibits featured lions. If the zoo features 24 exhibits in total, then how many of
Sauron [17]
12 exhibits featured lions since half of 24 is 12.
3 0
3 years ago
Read 2 more answers
A population has a mean of 200 and a standard deviation of 50. Suppose a sample of size 100 is selected and x is used to estimat
zmey [24]

Answer:

a) 0.6426 = 64.26% probability that the sample mean will be within +/- 5 of the population mean.

b) 0.9544 = 95.44% probability that the sample mean will be within +/- 10 of the population mean.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 200, \sigma = 50, n = 100, s = \frac{50}{\sqrt{100}} = 5

a. What is the probability that the sample mean will be within +/- 5 of the population mean (to 4 decimals)?

This is the pvalue of Z when X = 200 + 5 = 205 subtracted by the pvalue of Z when X = 200 - 5 = 195.

Due to the Central Limit Theorem, Z is:

Z = \frac{X - \mu}{s}

X = 205

Z = \frac{X - \mu}{s}

Z = \frac{205 - 200}{5}

Z = 1

Z = 1 has a pvalue of 0.8413.

X = 195

Z = \frac{X - \mu}{s}

Z = \frac{195 - 200}{5}

Z = -1

Z = -1 has a pvalue of 0.1587.

0.8413 - 0.1587 = 0.6426

0.6426 = 64.26% probability that the sample mean will be within +/- 5 of the population mean.

b. What is the probability that the sample mean will be within +/- 10 of the population mean (to 4 decimals)?

This is the pvalue of Z when X = 210 subtracted by the pvalue of Z when X = 190.

X = 210

Z = \frac{X - \mu}{s}

Z = \frac{210 - 200}{5}

Z = 2

Z = 2 has a pvalue of 0.9772.

X = 195

Z = \frac{X - \mu}{s}

Z = \frac{190 - 200}{5}

Z = -2

Z = -2 has a pvalue of 0.0228.

0.9772 - 0.0228 = 0.9544

0.9544 = 95.44% probability that the sample mean will be within +/- 10 of the population mean.

7 0
3 years ago
£6000 is divided between Adam, Ben and<br> Chris in the ratio 1:3:4. How much does Ben receive?
Gala2k [10]

Answer:

Chris gets £3000

Step-by-step explanation:

A : B : C

1 : 3 : 4 = 8 (add all the parts together)

£6000 ÷ 8 = 750

so the multiplier is x 750

1 : 3 : 4

↩ x 750

750 : 2250 : 3000

Chris gets £3000

3 0
2 years ago
(4x³-5x+10) ÷ (x+1)​
zlopas [31]

Answer:

4x^2 − 4x −1 + 11 / x+1

Step-by-step explanation:

The answer is

4x^2 − 4x −1 + 11 / x+1

4 0
3 years ago
Read 2 more answers
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