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Alex_Xolod [135]

3 years ago

10

PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU B

RAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!!PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!

2 answers:

Sophie [7]3 years ago

7 0

Answer:

All integers are rational numbers

Step-by-step explanation:

Since any integer can be written as the ratio of two integers, all integers are rational numbers. Remember that all the counting numbers and all the whole numbers are also integers, and so they, too, are rational.

klemol [59]3 years ago

7 0

Answer:

True

Step-by-step explanation:

An integer is a number including positive and negatives with 0 that are whole numbers and are not fractions or decimals

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For the equation 3x - 5y = -3, what is the value of y when x is 1?<br><br> 6/5<br> -6/5<br> 5/6

babymother [125]

Answer:

$\frac{-6}{5}$

Step-by-step explanation:

$3(1) - 5y = -3\\3 - 5y = -3\\-3 \\5y = -6\\/5 \\\\\frac{-6}{5}$

3 0

3 years ago

Read 2 more answers

How many 10-digit ternary strings are there that contain exactly two 0s, three 1s, and five 2s?

Svet_ta [14]

There are $\dbinom{10}2$ ways of picking 2 of the 10 available positions for a 0. 8 positions remain.

There are $\dbinom83$ ways of picking 3 of the 8 available positions for a 1. 5 positions remain, but we're filling all of them with 2s, and there's $\dbinom55=1$ way of doing that.

So we have

$\dbinom{10}2\dbinom83\dbinom55=\dfrac{10!}{2!(10-2)!}\dfrac{8!}{3!(8-3)!}\dfrac{5!}{5!(5-5)!}=2520$

The last expression has a more compact form in terms of the so-called multinomial coefficient,

$\dbinom{10}{2,3,5}=\dfrac{10!}{2!3!5!}=2520$

5 0

3 years ago

solve the system of equations below by graphing both equations with a pencil and paper. what is the solution y = x - 1 y = 1/2x

Elan Coil [88]

Answer:

(4,3)

Step-by-step explanation:

$(x-1) = \frac{1}{2}x +1$

$(x-\frac{1}{2}x)-(-1+1)=(\frac{1}{2}x-\frac{1}{2}x)+(1+1)$

$(\frac{1}{2}x/\frac{1}{2})=(2/\frac{1}{2})$

$x=4$

$y=(4)-1$

$y=3$

$y=\frac{1}{2}(4)+1$

$y=2+1$

$y=3$

6 0

4 years ago

Use properties of limits and algebraic methods to find the limit, if it exists. (If the limit is infinite, enter '[infinity]' or

soldi70 [24.7K]

Answer:

The limit of this function does not exist.

Step-by-step explanation:

$\lim_{x \to 3} f(x)$

$f(x)=\left \{ {{9-3x} \quad if \>{x \>< \>3} \atop {x^{2}-x }\quad if \>{x\ \geq \>3 }} \right.$

To find the limit of this function you always need to evaluate the one-sided limits. In mathematical language the limit exists if

$\lim_{x \to a^{-}} f(x) = \lim_{x \to a^{+}} f(x) =L$

and the limit does not exist if

$\lim_{x \to a^{-}} f(x) \neq \lim_{x \to a^{+}} f(x)$

Evaluate the one-sided limits.

The left-hand limit

$\lim_{x \to 3^{-} } 9-3x= \lim_{x \to 3^{-} } 9-3*3=0$

The right-hand limit

$\lim_{x \to 3^{+} } x^{2} -x= \lim_{x \to 3^{+} } 3^{2}-3 =6$

Because the limits are not the same the limit does not exist.

8 0

4 years ago

Please need help on this

artcher [175]

Answer:

the center is (-4,7) and the radius is 3

Step-by-step explanation:

The center of a circle can be found using the equation $(x-h)^2 + (y-k)^2 = r^2$ and is (h,k) from it. Notice h and k are the opposite value as in the equation.

First write the equation in this form.

$x^2 + 8x + ( ?)+ y^2 - 14y + (?) + 56 = 0$

Complete the square with each variable to find what numbers should go in place of the question marks.

$(8/2)^2 = 4^2 = 16$

$(-14/2)^2 = -7^2 = 49$

Add 16 and 49 to both sides of the equation.

$x^2 + 8x + 16 + y^2 - 14y + 49 + 56 = 16 + 49\\(x+4)^2 + (y-7)^2 + 56 = 65\\(x+4)^2 + (y-7)^2 = 9$

So the center is (-4,7) and the radius is 3.

5 0

3 years ago