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Alex73 [517]
3 years ago
15

X-2/3=1/3 this is the problem

Mathematics
2 answers:
tia_tia [17]3 years ago
7 0
The answer is 3/3 or 1
Sergio039 [100]3 years ago
3 0
Solving for x I suppose....
cross multiply....
3x-6 = 3
3x = 9
x = 3

x-2 = 1
-----  ----
 3      3
Cross multiply and get 3x-6 = 3
add 6 to each side and get
3x = 9
divide each side by 3 and get
x = 3
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At what points are the equation y=x^2 and 1/x+2 equal<br><br>​
irina [24]

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Brown, purple, Green and Red/Pink

Step-by-step explanation:

The equations are equal where they intersect on the graph. There are 4 points at which the to graphs intersect. They intersect at the points colored brown, purple, green and red.

6 0
3 years ago
Consider a family that generates 20 loads of laundry in a week. based on the data in the table, what is the total number of peop
liq [111]

The total number of people in the family that generates 20 loads of laundry in a week is 10.

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An equation is an expression that shows the relationship between two or more numbers and variables.

Let y represent the number of people and x represent the number of laundry loads.

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5 0
1 year ago
What are the roots of this quartaic equation?<br> -102 + 12r - 9 = 0
elena-14-01-66 [18.8K]

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7 0
3 years ago
Read 2 more answers
It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp​
Semmy [17]

Answer:

\frac{1}{5}

Step-by-step explanation:

Using the rules of exponents

a^{m} × a^{n} = a^{(m+n)}, \frac{a^{m} }{a^{n} } = a^{(m-n)}, (a^m)^{n} = a^{mn}

Simplifying the product of the first 2 terms

\frac{a^{p^2+pq} }{a^{pq+q^2} } × \frac{a^{q^2+qr} }{a^{qr+r^2} }

= a^{p^2-q^2} × a^{q^2-r^2}

= a^{p^2-r^2}

Simplifying the third term

5((a^p+r)^{p-r}

= 5a^{(p+r)(p-r)} = 5a^{(p^2-r^2)}

Performing the division, that is

\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} } ← cancel a^{(p^2-r^2)} on numerator/ denominator leaves

= \frac{1}{5}

4 0
3 years ago
Help me answer 1 and 2 please
Fittoniya [83]
I think 1 is -540 and 2 is -290
8 0
3 years ago
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