If a,b,c are the 3 positive integers
1/a +1/b +1/c > 6/abc
(bc+ac+ab)/abc >6/abc so
(bc+ac+ab)>6
The lowest positive integers that are different are 1,2,3 so the lowest value that (bc+ac+ab) could have is 1•2+2•3+1•3=2+6+3= 11 therefore
1/a +1/b +1/c > 6/abc is true
-3(-4y+3) +7y
Expand
12y-9+7y
Add like terms
19y-9
Answer:
Step-by-step explanation:
Remember simple multiplication? Write the problem with 17 at the bottom:
8
* 1 7
----------
5 6 <-- this is 8*7
8 0 <-- this is 8*10 [we sometimes just shift and don't write the 0]
-------
1 3 6
So, 8*17 is the same as 8*10 + 8*7.
Answer:
a. 126
b. 15120
Step-by-step explanation:
5 chose 9 = 9 * 8 * 7 * 6 * 5/1/2/3/4/5 = 126
if order matters...
9*8*7*6*5 = 15120
Answer:
wow
Step-by-step explanation:
